Integrating P along Curve c: A Math Challenge

Click For Summary

Homework Help Overview

The discussion revolves around evaluating the integral of the function P = 2xyz^2 along a specified curve defined parametrically by x=t^2, y=2t, and z=t^3, with t ranging from 0 to 1. Participants are exploring the complexities involved in computing this line integral.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to express P in terms of the parameter t and the challenges associated with calculating the magnitude of r'(t). There are suggestions to consider completing the square and using integration by parts. Some participants express uncertainty about the expectations for solving the integral, questioning whether standard methods are required.

Discussion Status

The conversation is ongoing, with various approaches being considered, including the potential application of theorems like Green's or Stokes'. However, participants note that the curve is not closed, which limits the applicability of these theorems. There is no explicit consensus on a method, but several lines of reasoning are being explored.

Contextual Notes

Participants mention the complexity of the integral and express concern about the expectations set by the instructor regarding the method of solution. There is an acknowledgment of the integral's difficulty, with references to external resources for further insight.

joe:)
Messages
28
Reaction score
0

Homework Statement



So I'm trying to find the integral of P = 2xyz^2 along the curve c which is defined by:

x=t^2
y=2t
z=t^3

t goes from 0 to 1

So the q says that it is the integral of P dr along c


Homework Equations





The Attempt at a Solution



So I know that this should equal the integral of P times mod r'(t) dt..

But if r = (t^2, 2t, t^3) then mod of r'(t) is pretty ugly..and I can't solve the integral..

Any pointers?
 
Physics news on Phys.org
Line Integral of Scalar Function

1. Homework Statement

So I'm trying to find the integral of P = 2xyz^2 along the curve c which is defined by:

x=t^2
y=2t
z=t^3

t goes from 0 to 1

So the q says that it is the integral of P dr along c


2. Homework Equations



3. The Attempt at a Solution

So I know that this should equal the integral of P times mod r'(t) dt..

But if r = (t^2, 2t, t^3) then mod of r'(t) is pretty ugly..and I can't solve the integral..

Any pointers?
 
Write P in terms of t?
 
joe:) said:
So I know that this should equal the integral of P times mod r'(t) dt..

But if r = (t^2, 2t, t^3) then mod of r'(t) is pretty ugly..and I can't solve the integral..

Any pointers?

I have to admit I don't know either, but I'm fairly confident the teacher doesn't expect you to solve the integral using the "standard" method. Here's how complicated the improper integral is:

http://integrals.wolfram.com/index.jsp?expr=x^9*sqrt%289*x^4%2B4x^2%2B4%29&random=false
 


joe:) said:
So I know that this should equal the integral of P times mod r'(t) dt..

But if r = (t^2, 2t, t^3) then mod of r'(t) is pretty ugly..and I can't solve the integral..

Any pointers?

You might want to start by completing the square on [itex]||\textbf{r}'(t)||^2[/tex] and then make an appropriate substitution. Even then, it looks like you will need to use integration by parts several times.[/itex]
 
(Two threads merged and moved to Calculus & Beyond)

Please do not multiple post questions here, Joe. Thanks.
 
ideasrule said:
I have to admit I don't know either, but I'm fairly confident the teacher doesn't expect you to solve the integral using the "standard" method. Here's how complicated the improper integral is:

http://integrals.wolfram.com/index.jsp?expr=x^9*sqrt%289*x^4%2B4x^2%2B4%29&random=false

Hmm yes, complicated indeed!

Is there a theorem I can use? Greens? Stokes?
 
joe:) said:
Hmm yes, complicated indeed!

Is there a theorem I can use? Greens? Stokes?

I don't see any tricks to make this one easier. Your curve isn't closed, so it doesn't bound a surface and certainly doesn't enclose a volume so Green's and Stokes' theorems won't help. The fundamental theorem for gradients also doesn't seem to help here (I can't think of a scalar function for which [itex]\mathbf{\nabla}\Phi\cdot d\textbf{r}=Pdr[/itex]...can you?) I also don't see any tricks involving the limits of integration, so it seems to me like you will have to do it the "standard way" if you are required to calculate the integral analytically.

For the "standard way", I stand by my earlier suggestion.
 

Similar threads

Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
12
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K