Integrating Partial Derivatives

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SUMMARY

The discussion centers on solving a system of first-order partial differential equations defined by the equations df/dx = 4x^3 - 4xy^2 + cos(x) and df/dy = -4yx^2 + 4y^3. The user integrated both equations to obtain potential solutions, x^4 - 2x^2y^2 + sin(x) + c(y) and -2y^2x^2 + y^4 + c(x). The key insight is that the function c(y) must be determined by differentiating the first solution with respect to y and ensuring it satisfies the second equation, confirming that both solutions yield the same result.

PREREQUISITES
  • Understanding of first-order partial differential equations
  • Knowledge of integration techniques for multivariable functions
  • Familiarity with the concept of arbitrary functions in differential equations
  • Experience with differentiating functions with respect to multiple variables
NEXT STEPS
  • Study the method of characteristics for solving partial differential equations
  • Learn about the implications of arbitrary functions in solutions of differential equations
  • Explore the relationship between different forms of solutions in partial differential equations
  • Investigate the role of boundary conditions in determining unique solutions
USEFUL FOR

Mathematics students, educators, and researchers focusing on differential equations, particularly those interested in the integration and solution of partial differential equations.

rudders93
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Homework Statement


Find the general function f(x,y) that satisifes the following first-order partial differential equations

[tex]\frac{df}{dx}=4x^3 - 4xy^2 + cos(x)[/tex]
[tex]\frac{df}{dy}=-4yx^2 + 4y^3[/tex]

The Attempt at a Solution



I integrated both to get:

[tex]x^4 - 2x^2y^2 + sin(x) + c(y)[/tex]

and

[tex]-2y^2x^2 + y^4 + c(x)[/tex]

I'm not to sure what it means by the most general function that satisifes both. Like I'm assuming that means it's just some function that I can sub into both partial derivatives and get the same result? If so, what is a systematic way of doing so?

Thanks!
 
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Like I'm assuming that means it's just some function that I can sub into both partial derivatives and get the same result?

I don't know what you mean by "get the same result", but it's some function that satisfies both partial differential equations.

Let's focus on your first solution: [tex]x^4 - 2x^2y^2 + sin(x) + c(y)[/tex]

We know that the second differential equation imposes some extra conditions on c(y), so try differentiating this solution with respect to y and comparing with the second differential equation to see what c(y) must be.

You might wonder why I chose the first solution instead of the second. That's because the two give the same answer. If they didn't, the system of equations would have no solution.
 

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