Integrating w/o U-Substitution

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SUMMARY

The integral of the function e^(-2x^2) cannot be evaluated using standard methods and does not yield an elementary function. This integral is closely related to the Gaussian integral, ∫e^(-x^2)dx, which requires the substitution u = √2x for simplification. The error function, erf(x), is introduced as a related concept, representing the integral of e^(-x^2) between finite bounds. The definite integral can be evaluated using polar coordinates, but the indefinite integral remains non-elementary.

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Homework Statement


∫y=e^(-2x^2)dx

Homework Equations


The Attempt at a Solution


I can't recall any method for this. I know that the integral of e^x is e^x, but I know that in this case the integral would not be the same as the original function because the derivative of -2x^2 would be -4x. Can anyone help me?
 
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Short answer: You can't evaluate that integral in the usual way.

Long answer: This is related to the Gaussian integral:

[tex]\int_{-\infty}^{\infty}e^{-x^2}dx[/tex]

which you should be able to see by making the substitution [itex]u = \sqrt{2}x[/itex] into your integral.

The indefinite integral of the function [itex]e^{-x^2}[/itex] cannot be expressed in terms of elementary functions. There is a related function, called the error function, written as [itex]erf(x)[/itex], which involves a definite integral of the same function between finite bounds [itex]0[/itex] and [itex]x[/itex]. Again, the error function cannot be expressed in terms of elementary functions, and is simply defined in terms of that integral.
 
definite integral of it can be evaluated between limits 0 to infinity by transforming to polar coordinates.
 

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