ineedhelpnow Messages 649 Reaction score 0 Jul 6, 2014 #31 what do i do once i have $\frac{1}{64(sec\theta)^2}$
MarkFL Gold Member MHB Messages 13,284 Reaction score 12 Jul 6, 2014 #32 ineedhelpnow said: what do i do once i have $\frac{1}{64(sec\theta)^2}$ Well, you need to change your differential and limits in accordance with the substitution...we have let: $$\frac{1}{y}=8\tan(\theta)\,\therefore\,y=\frac{1}{8}\cot(\theta)\,\therefore\,dy=-\frac{1}{8}\csc^2(\theta)\,d\theta$$ Now, from our substitution, we find: $$\theta=\tan^{-1}\left(\frac{1}{8y}\right)$$ and so we use this to change our limits from $y$'s to $\theta$'s. Can you put all of this together to express the remaining integral in terms of $\theta$?
ineedhelpnow said: what do i do once i have $\frac{1}{64(sec\theta)^2}$ Well, you need to change your differential and limits in accordance with the substitution...we have let: $$\frac{1}{y}=8\tan(\theta)\,\therefore\,y=\frac{1}{8}\cot(\theta)\,\therefore\,dy=-\frac{1}{8}\csc^2(\theta)\,d\theta$$ Now, from our substitution, we find: $$\theta=\tan^{-1}\left(\frac{1}{8y}\right)$$ and so we use this to change our limits from $y$'s to $\theta$'s. Can you put all of this together to express the remaining integral in terms of $\theta$?