Integration by parts — 400 discussions
-
Undergrad Find ##\int_0^π \sin^ n x dx ##
$$\int_0^π \sin^ n x dx = \int_0^π \sin^ {n-1} x\sin x dx$$ Letting ##u=\sin^{n-1} x## and ##v^{'}= \sin x## then, $$\int_0^π \sin^ {n-1} x\sin x dx = [-\sin^ {n-1} x⋅\cos x]_0^π+ \int_0^π (n-1)\sin^{n-2} x ⋅ \cos^2 x dx$$ $$=\int_0^π... -
Graduate Dirac "GTR" Eq. 27.11 -- how to show that a boundary term vanishes?
In Dirac's "General Theory of Relativity", p. 53, eq. (27.11), Dirac is deriving Einstein's field equations and the geodesic equation from the variation ##\delta(I_g+I_m)=0## of the actions for gravity and matter. Here ##p^\mu=\rho v^\mu \sqrt{-g}## is the momentum of an element of matter. He...- Kostik
- Thread
- Divergence theorem General relativity Geodesic equation Integration by parts
- Replies: 4
- Forum: Special and General Relativity
-
S
Undergrad Did Math DF's integral calculator make a glaring mistake?
In calculating the integral ##\int{\ln\left(x\right)\,\sin\left(x\right)\,\cos\left(2\,x\right)}{\;\mathrm{d}x}##, I used a few online integral calculators to check my answer. According to one calculator, I got the correct antiderivative, but according to another (Math DF Integral Calculator)...- SmartyPants
- Thread
- Antiderivative Integration by parts
- Replies: 8
- Forum: Calculus
-
Finding the Fourier cosine series for ##f(x)=x^2##
I was just going through my old notes on this i.e The concept is straight forward- only challenge phew :cool: is the integration bit...took me round and round a little bit... that is for ##A_n## part. My working pretty ok i.e we shall realize the text solution. Kindly find my own working...- chwala
- Thread
- Integration by parts Software
- Replies: 4
- Forum: Calculus and Beyond Homework Help
-
High School Integration by parts for ∫sin⁻¹x dx
Hi, PF, here goes an easy integral, meant to be an example of integration by parts. Use integration by parts to evaluate ##\int \sin^{-1}x \, dx## Let ##U=\sin^{-1}x,\quad{dV=dx}## Then ##dU=dx/\sqrt{1-x^2},\quad{V=x}## ##=x\sin^{-1}x-\int \frac{x}{\sqrt{1-x^2} \, dx}## Let ##u=1-x^2##...- mcastillo356
- Thread
- Integral Integration by parts Integration by substitution
- Replies: 4
- Forum: Calculus
-
High School Why use K instead of C for the constant in integration by parts
Hi, PF Integration by parts is pointed out this way: Suppose that ##U(x)## and ##V(x)## are two differentiable functions. According to the Product Rule, $$\displaystyle\frac{d}{dx}\big(U(x)V(x)\big)=U(x)\displaystyle\frac{dV}{dx}+V(x)\displaystyle\frac{dU}{dx}$$ Integrating both sides of...- mcastillo356
- Thread
- Confused Integration by parts Introduction
- Replies: 2
- Forum: Calculus
-
S
Solving this definite integral using integration by parts
Using integration by parts: $$I_n=\left. x(1+x^2)^{-n} \right|_0^1+\int_0^{1} 2nx^2(1+x^2)^{-(n+1)}dx$$ $$I_n=2^{-n} + 2n \int_0^{1} x^2(1+x^2)^{-(n+1)}dx$$ Then how to continue? Thanks- songoku
- Thread
- Calculus Definite integral Integral Integration Integration by parts Mathematics parts
- Replies: 3
- Forum: Calculus and Beyond Homework Help
-
Undergrad Verifying Integration of ##\int_0^1 x^m \ln x \, \mathrm{d}x##
I'm trying to compute ##\int_0^1 x^m \ln x \, \mathrm{d}x##. I'm wondering if the bit about the application of L'Hopital's rule was ok. Can anyone check? Letting ##u = \ln x## and ##\mathrm{d}v = x^m##, we have ##\mathrm{d}u = \frac{1}{x}\mathrm{d}x ## and ##v = \frac{x^{m+1}}{m+1}##...- murshid_islam
- Thread
- Integral calculus Integration Integration by parts L'hopital's rule Limit
- Replies: 1
- Forum: Calculus
-
A
Graduate Feynman parametrization integration by parts
How can i move from this expression: $$\frac{4}{\pi^{4}} \int dk \frac{1}{k^2} \frac{1}{(1+i(k-k_{f}))^3} \frac{1}{(1+i(k-k_{i}))^3}$$ to this one: $$\frac{4}{\pi^{4}} \int dk \frac{1}{k^2} \frac{1}{(1+|k-k_{i}|^2)^2} \frac{1}{(1+|k-k_{f}|^2)^2}$$ using Feynman parametrization (Integration by...- asmae
- Thread
- Feynman Integration Integration by parts Parametrization parts
- Replies: 1
- Forum: High Energy, Nuclear, Particle Physics
-
Rewriting a given action via integration by parts
I simply plugged \phi = \phi_0 (\eta) + \delta \phi (\eta, \vec x) into the given action to get \begin{align} S &= \int d^4 x \left[ \frac{a^2}{2}\left(\dot \phi^2 -(\nabla \phi)^2\right)-a^4V(\phi) \right] \nonumber \\ &= \int d^4 x \left[ \frac{a^2}{2}\left(\dot \phi_0^2 + (\delta...- JD_PM
- Thread
- Integration Integration by parts parts
- Replies: 5
- Forum: Advanced Physics Homework Help
-
High School Why don't we account for the constant in integration by parts?
As we all know, integration by parts can be defined as follows: $$\int u dv = uv - \int v du$$ And the usual strategy for solving problems of these types is to intelligently define ##u## and ##dv## such that the RHS integral can easily be evaluated. However, something that is never addressed is... -
Undergrad How to interpret integration by parts
So I am confused about a proof in which the formula for expected value of velocity, ##\frac{d\langle x \rangle}{dt} ##, is derived. Firstly, because the expected value of the position of wave function is $$\langle x \rangle =\int_{-\infty}^{+\infty} x|\Psi(x,t)|^2 dx$$Therefore...- Tony Hau
- Thread
- Integration Integration by parts parts
- Replies: 11
- Forum: Quantum Physics
-
B
Integrating with a Denominator of (1+x^2)
I think in the case of "n da" you can see the denominator (1+x^2) as a constant, so ∫ ( sin(a) + M^2 ) / ( 1 + x^2 ) da = ( 1 / ( 1 + x^2 ) ) * ∫ (sin(a) + M^2 ) da = ( 1 / ( 1 + x^2 ) ) * ( -cos(a) + (M^2)a ) = ( - cos(a) + (M^2)a ) / ( 1 + x^2 ) --- Is this the way to go? This is my...- beertje
- Thread
- Integration Integration by parts
- Replies: 2
- Forum: Calculus and Beyond Homework Help
-
Integration problem using Integration by Parts
i would appreciate alternative method...- chwala
- Thread
- Integration Integration by parts parts
- Replies: 4
- Forum: Calculus and Beyond Homework Help
-
Undergrad Integrate 1/(x*lnx): Integration by Parts
can integrate 1/(x*lnx) by parts??- LCSphysicist
- Thread
- Integration Integration by parts parts
- Replies: 3
- Forum: Calculus
-
Undergrad Bernoulli Equation with weird integral
Part of me thinks this is could be a u-sub b/c x^3's derivative is 3x^2, a factor of 3 off from what e is raised to...but it is not a traditional u-sub...any thoughts if this is a u-sub or by parts, and what u should be?I know that there is more to solving the equation after this ( z =...- acalcstudent
- Thread
- Bernoulli Bernoulli equation Integral Integration by parts Weird
- Replies: 1
- Forum: Differential Equations
-
Graduate Understanding Integration by Parts in Quantum Field Theory
Hello, I'm just starting Zee's QFT in a Nutshell, I'm a bit confused about what he means by "integate by parts under the d4x". Can someone explain what he means by this? I understand how to obtain the Klein-Gordon equation from the free particle Lagrangian density, but not sure why he invokes...- looseleaf
- Thread
- Integration Integration by parts parts
- Replies: 2
- Forum: High Energy, Nuclear, Particle Physics
-
Undergrad Solving Quantum Mechanics Integral Equation: How to Get from (1) to (2)?
The book on quantum mechanics that I was reading says: d<x>/dt = d/dt ∫∞-∞ |ψ(x,t)|2 dx =iħ/2m ∫∞-∞ x∂/∂x [ψ∂ψ*/∂x+ψ*∂ψ/∂x]dx (1) =-∫∞-∞ [ψ∂ψ*/∂x+ψ*∂ψ/∂x]dx (2) I want to know how to get from (1) to (2) The book says you use integration by part: ∫abfdg/dx dx = [fg]ab - ∫abdf/df dg dx I chose f...- physics bob
- Thread
- Integral Integral equation Integration by parts Wave function
- Replies: 4
- Forum: Quantum Physics
-
S
How Do You Correctly Apply Integration by Parts to ∫-e^(2x)*sin(e^x) dx?
Homework Statement I want to integrate ∫-e^(2x)*sin(e^x) dx Homework Equations ∫uv'dx=uv - ∫u'v The Attempt at a Solution u = e^2x du = 2*e^2x dv = sin(e^x) v = -cos(e^x)/e^x e^(x)*cos(e^x) - 2∫e^(x)*cos(e^x) dx e^(x)*cos(e^x) - 2*sin(e^x) + c The solution I have doesn't have the two in...- shreddinglicks
- Thread
- Integration Integration by parts parts
- Replies: 9
- Forum: Calculus and Beyond Homework Help
-
What is the primitive of sinx/cos^2x?
Homework Statement ∫e^(-x)(1-tanx)secx dx 2. Attempt at a solution I know ∫e^x(f(x)+f'(x))=e^x f(x) and I intuitively know f(x) could be secx here and therefore f'(x) will be secxtanx but I can't figure out how to reach that- Krushnaraj Pandya
- Thread
- Integration Integration by parts parts
- Replies: 3
- Forum: Calculus and Beyond Homework Help
-
Integration by parts, Partial fraction expansion, Improper Integrals
- check if right check if right Now, 2 seems to be the right answer for A yet when i made x=5 and subtracted new form form the old one I got a difference of ~$\frac{4}{9}$ (should be 0 obviously) I got A=2 B=$\frac{45}{21}$ C=2 How to calculate $\lim_{{x}\to{\infty}}(- e^{-x})$ -
R
Undergrad Solving Integration by Parts for Relativistic Kinetic Energy
Hi, I've been following a derivation of relativistic kinetic energy. I've seen other ways to get the end result but I'm interested in finding out where I've gone wrong here: I'm struggling with integrating by parts. The author goes from... -
L
Visualization of Integration by Parts
Hello all, I am trying to understand the rational behind the visualization of integration by parts, however I struggle with it a wee bit. I was trying to read about it in Wiki, this is what I found... -
Graduate Integration by parts of a differential
I'll cut the long story short. What on Earth happened here: I seem to be unable to do the integration by parts of the first term. I end up with a lot of dx's. -
Integration by Parts with Logarithmic Functions
Homework Statement ##\displaystyle \int \frac{\log (x)}{x}~ dx## Homework EquationsThe Attempt at a Solution I am a little confused about the first part. We know that the ##\displaystyle \int \frac{1}{x}~ dx = \log |x|##. So how can we proceed with integration by parts if one of the logs has...- Mr Davis 97
- Thread
- Integration Integration by parts parts
- Replies: 13
- Forum: Calculus and Beyond Homework Help
-
Integration By Parts: uv-Substitution - 9.2
$\tiny{9.2}$ \begin{align*} \displaystyle I&=\int y^3e^{-9y} \, dx\\ \textit{uv substitution}\\ u&=y^3\therefore \frac{1}{3}du=y^2dx\\ dv&=e^{-9y}\, dx\therefore v=e^{-9y}\\ \end{align*} will stop there this looks like tabular method better -
Integration by Parts Twice: How to Solve Tricky Integrals
Homework Statement Integrate e^3x sin x. Homework Equations uv - Integral(v du) The Attempt at a Solution I am trying to help somebody else with this problem, as I took Calculus a few years ago, but the end is really kicking my butt. I know I'm VERY close, but once I get to the second...- EthanVandals
- Thread
- Integration Integration by parts parts
- Replies: 1
- Forum: Calculus and Beyond Homework Help
-
Undergrad Laplacian in integration by parts in Jackson
I am reviewing Jackson's "Classical Electromagnetism" and it seems that I need to review vector calculus too. In section 1.11 the equation ##W=-\frac{\epsilon_0}{2}\int \Phi\mathbf \nabla^2\Phi d^3x## through an integration by parts leads to equation 1.54 ##W=\frac{\epsilon_0}{2}\int |\mathbf...- Angelo Cirino
- Thread
- Electromagnatism Integration Integration by parts Jackson Laplacian parts Vector calculus
- Replies: 4
- Forum: Beyond the Standard Models
-
Delta property, integration by parts, heaviside simple property proof
Homework Statement I am trying to show that ## \int \delta (x-a) \delta (x-c) dx = \delta (-a-c) ## via integeration by parts, but instead I am getting ##\delta (c-a) ## (or ##\delta (a-c)## depending how I go...). Can someone please help me out where I've gone wrong: struggling to spot it...- binbagsss
- Thread
- Delta Heaviside Integration Integration by parts parts Proof Property
- Replies: 9
- Forum: Calculus and Beyond Homework Help
-
P
Undergrad Integrating sqrt(x) cos(sqrt(x)) dx
Question: sqrt(x) cos(sqrt(x)) dx My try: Let dv = cos(√x) => v = 2√xsin(√x) and u = √x => du = dx/(2√x) Using integration by parts, we get ∫√x cos(√x) dx = 2√x√x sin(√x) - ∫(2√xsin(√x) dx)/(2√x) = 2x sin(√x) - ∫sin(√x) dx = 2x sin(√x) + 2 cos(√x) √x However, the answer given in the book... -
S
Undergrad Integration by Parts without using u, v
Hello, I'm currently taking calc 1 as an undergraduate student, and my professor just showed us a new? way of solving Integration By Parts. This is the example he gave" Is there a name for this technique that substitutes d(___) instead of dx? Thank you,- Sang Ho Lee
- Thread
- Integration Integration by parts parts
- Replies: 2
- Forum: Calculus
-
Solve Difficult Integral: ∫ex t-2 dt
Homework Statement Hi, I'm doing a variation of parameters problem for my differential equations class. It requires solving the integral: ∫ex t-2 dt I am sure my professor did not give me an impossible integral and that there is some algebraic "trick" to solving it, but despite going through...- Prof. 27
- Thread
- Integral Integration Integration by parts
- Replies: 4
- Forum: Calculus and Beyond Homework Help
-
Integration by parts and approximation by power series
Homework Statement An object of mass m is initially at rest and is subject to a time-dependent force given by F = kte^(-λt), where k and λ are constants. a) Find v(t) and x(t). b) Show for small t that v = 1/2 *k/m t^2 and x = 1/6 *k/m t^3. c) Find the object’s terminal velocity. Homework...- Elvis 123456789
- Thread
- Approximation Calculus Differential equation Integration Integration by parts parts Power Power series Series
- Replies: 6
- Forum: Calculus and Beyond Homework Help
-
E
Graduate Triple Product in Laplace Transform
Hello - I'm not sure this is where this should go, but I'm working with Laplace Transforms and differential equations, so this seems as good a place as any. Also, I doubt this is graduate level math strictly speaking, but I went about as high as you can go in calculus and linear algebra during...- echandler
- Thread
- Differential equation Infinite series Integration by parts Laplace Laplace transform Product Transform
- Replies: 2
- Forum: Differential Equations
-
C
Why does the integral of √(a² +x²) need Integration by parts?
Why this integral $\int\left\{\sqrt{{a}^{2}+{x}^{2}}\right\}dx$ needs integration by parts? Thanks Cbarker1 -
How is Integration by Parts Applied to $\int_{0}^{\pi} x^3 \cos(x) \, dx$?
$\Large {S6-7.1.24}$ $$ \displaystyle I=\int_{0}^{\pi} {x}^{3}\cos\left({x}\right)\,dx=12-3{\pi}^{2} \\ \begin{align} u& = {{x}^{3}} & dv&=\cos\left({x}\right) \, dx \\ du&={3x^2} \ d{x}& v&={\sin\left({x}\right)} \end{align} \\ $$ $$ \text{IBP} \displaystyle =uv-\int v\ du \\... -
How Can You Master Integration by Parts with the Formula and Examples?
|3^xlog3dxI don't even know where to start. I know that the formula is |u.dv = uv - |v.du u=3^x v=log3- Electgineer99
- Thread
- Integration Integration by parts Logarithms parts
- Replies: 13
- Forum: Calculus and Beyond Homework Help
-
C
Integration by Parts: Solving Integrals with √(1+x^2) and x
Homework Statement [/B] Homework Equations ∫ f(x) g'(x) dx = f(x) g(x) - ∫ f '(x) g(x) dx f(x)=√(1+x^2) f '(x)=x * 1/√(1+x^2) g'(x)=1 g(x)=x The Attempt at a Solution ∫ √(1+x^2) * 1 dx =x * √(1+x^2) - ∫ x^2 * 1/√(1+x^2) dx Further integration just makes the result look further from what...- Chris Fernandes
- Thread
- Calculus Integration Integration by parts parts
- Replies: 2
- Forum: Calculus and Beyond Homework Help
-
T
Undergrad Vector Triple Product Identity and Jacobi Identity for Deriving 4B.10 and 4B.11
I was trying to derive the following results from 4B.8 as suggested by using the vector triple product identity but have been unsuccessful in deriving ##\vec{L_R}## and ##\vec{S_R}## in the end. After using the identity and finding the integrand to be ## \vec{E}(\vec{r}\cdot\vec{B}) - \vec{B}...- TheCanadian
- Thread
- Integration Integration by parts parts Vector
- Replies: 2
- Forum: Calculus
-
F
Undergrad How Can I Correctly Integrate e^(ix)cos(x)?
I'am trying to prove \int e^{ix}cos(x) dx= \frac{1}{2}x-\frac{1}{4}ie^{2ix} Wolfram tells so http://integrals.wolfram.com/index.jsp?expr=e^%28i*x%29cos%28x%29&random=false But I am stuck in obtaining the first term: My step typically involved integration by parts: let u=e^{ix}cos(x) and... -
F
Undergrad Unusual Limit: Understanding the Discrepancy in the Integral of xe^-x
This was just very basic, I have accepted it in just a heartbeat, but when I tried to chopped it and examined one by one, somethings fishy is happening, this just involved \int_{0}^{\infty}x e^{-x}dx=1. Well, when we do Integration by parts we will have let u = x du = dx dv = e^{-x}dx v =... -
M
Integration by parts with absolute function
Hi all, I have the average value of a function between limits of 7.3826 and 0 which equals 0.4453. I have used the formula for average value function and attached the equation I need solving as I don't know how to use the Latex commands. P is what I am trying to work out. Unfortunately I have... -
C
Possible integration by parts?
Homework Statement Integrate $$\int_0^1 dw \frac{w^{\epsilon+1} \ln((r+1-w)/r)}{1+r(1+w)}$$ for ##\epsilon## not necessarily an integer but positive and r is negative (<-1). The argument of the log is positive. Homework Equations Integration by parts The Attempt at a Solution [/B] I can...- CAF123
- Thread
- Integration Integration by parts parts
- Replies: 5
- Forum: Calculus and Beyond Homework Help
-
Graduate Integration by parts in curved space time
In this thread, ramparts asked how integration by parts could be used in general relativity. suppose you have ##\int_M (\nabla^a \nabla_a f) g .Vol## Can it be written like ##\int_M (\nabla^a \nabla_a g) f .Vol## plus a boundary integration term (by integrating twice by parts)? I think thay it...- naima
- Thread
- Curved space Integration Integration by parts parts Space Space time Time
- Replies: 13
- Forum: Special and General Relativity
-
Graduate Integration by parts in spacetime
In this paper we have p18 an integral on space time M. The author takes a 3 dimensional space like Cauchy surface ##\Sigma## which separates M in two regions, the future and the past of ##\Sigma##. He gets so the sum of two integrals on these regions. He writes then let us integrate each of them... -
Undergrad Integration by Parts: \int{\sin{(\theta)}*\cos{(\theta)}*d\theta}
The Integral: \int{\sin{(\theta)}*\cos{(\theta)}*d\theta} Attempt to solve by Integration by Parts: \int{u*dv} = u*v - \int{v*du} u = \sin{(\theta)} du = \cos{(\theta)}*d\theta v = \sin{(\theta)} dv = \cos{(\theta)}*d\theta Bringing back to the beginning.- Philosophaie
- Thread
- Integration Integration by parts parts
- Replies: 5
- Forum: Calculus
-
Graduate Average Speed for Maxwell's Distribution of Molecular Speed
Using the Maxwell-Boltzmann equation above, there is an example in my book (Giancoli 4th edition p. 481) where they use this to find the average velocity. I understand that it would just be the sum of all the speeds of the molecules divided by the number of molecules. But then I'm having...- RaulTheUCSCSlug
- Thread
- Average Average speed Boltzmann distribution Distribution Integration by parts Maxwell boltzmann Molecular Speed
- Replies: 2
- Forum: Electromagnetism
-
Integration by parts Theory Problem?
Find the second degree polynomial P(x) that has the following properties: (a) P(0)=1, (b) P'(0)=0, (c) the indefinite integral ∫P(x)dx/(x^3(x-1)^2). Note: the the indefinite integral is a rational function. Cannot have Log terms occurring in solution. first. I use the generic polynomial...- MidgetDwarf
- Thread
- Integration Integration by parts parts Theory
- Replies: 3
- Forum: Calculus and Beyond Homework Help
-
Why integration by parts doesn't need constants for intermediate integrals
Homework Statement While integrating by parts( by the formula) why don't we consider the contant of integration for every integral in the equation. Homework Equations $$∫uv = u∫v - ∫ ∫v . d/dx(u) $$ The Attempt at a Solution [/B] example. $$∫x \sin(x) dx = ?? $$ this is can be done like...- Suraj M
- Thread
- Integration Integration by parts parts
- Replies: 15
- Forum: Calculus and Beyond Homework Help
-
B
Integration by Parts: $\int u\cos(u)\,\mathrm{d}u$
I have the following integral \int e(2x) cos(ex). Let u = ex Do integration by parts: \int u2cos(u) du = u2sin(u) - \int (2usin(u) du Do integration by parts again for \int (2usin(u) du: \int (2usin(u) du = -2ucos(u) - \int -2cos(u) du Putting it all together: \int e(2x) cos(ex) =...- brunette15
- Thread
- Integration Integration by parts parts
- Replies: 3
- Forum: Calculus