How do I integrate u^-1 with new limits after substitution?

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The discussion revolves around integrating u^(-1) with new limits after a substitution in a calculus problem. The user initially struggles with the integration due to the form of u^(-1) and expresses confusion about the natural logarithm's application. They clarify that they assumed u is in a linear form and proceeded with the integration. Ultimately, they confirm that the final answer is ln(2) after receiving assistance. The thread highlights the importance of recognizing the natural logarithm in integration involving reciprocal functions.
markyp23
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Homework Statement



problem.jpg



Homework Equations



None. Well, dx=du/cosx

The Attempt at a Solution



I've substituted it in, got new values for the limits but I have u^-1 on the bottom and so can't integrate it from my current knowledge. Basically I'm stuck with:

Integration of u^(-1) du with limits of 1 and 2.

Any help appreciated. Apologies for not being able to work the Latex system.
 
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Seriously, you haven't encountered the derivative of the natural logarithm yet?
 
I have but I thought it had to be a linear expression to use the natural log. It did cross my mind though - this is what to do, then?
 
What do you mean by a "linear expression"??
 
Something of the form (ax+b).

Decided to assume that (u) is in that form and so worked it through. Is ln(2) the final answer?
 
Ask yourself:
May we write u=1*u+0?

Sure, the answer is ln2
 
Thanks for your help! :)
 

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