- #1
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This is a question...
For the following question:
[itex]y^{'}=\frac{dy}{dx}=3y[/itex]
I get the solution...
[itex]\int \frac{1}{3y} dy = \int dx[/itex]
[itex]\frac{1}{3}ln y = x + c[/itex]
[itex]y = e^{3x}+e^{3c}[/itex]
However the textbook example says the solution is...
[itex]y = ce^{3x}[/itex]
My question is would my answer be incorrect? How should the arbitrary constant be placed in ln and e integral solutions?
For the following question:
[itex]y^{'}=\frac{dy}{dx}=3y[/itex]
I get the solution...
[itex]\int \frac{1}{3y} dy = \int dx[/itex]
[itex]\frac{1}{3}ln y = x + c[/itex]
[itex]y = e^{3x}+e^{3c}[/itex]
However the textbook example says the solution is...
[itex]y = ce^{3x}[/itex]
My question is would my answer be incorrect? How should the arbitrary constant be placed in ln and e integral solutions?