Integration of x^n*e^x/(e^x + 1)^2

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The integral \( a_{n} = \int_{-\infty }^{\infty } \frac{x^n e^x}{(e^x+1)^2} \, dx \) can be expressed using the zeta function as \( a_{n} = (2 - \frac{1}{2^{2(n+1)}}) \zeta(2n) \), where \( \zeta(2n) = 2^{2n-1} \frac{\pi^{2n}}{(2n)!} B_{n} \) and \( B_n \) are the Bernoulli numbers. The discussion highlights the relationship between this integral and the series expansion involving even \( n \). Additionally, the user seeks alternative methods for solving the integral using complex analysis.

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Littlepig
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I there.

I'm currently using this kind of integrals, with n even, and I couldn't found anything in internet for calculate this.
Let From the book I'm studying Ashcroft/Mermin, Solid State Physics, Append C, it says that
[tex]a_{n}=\int_{-\infty }^{\infty } \frac{x^n<br /> e^x}{\left(e^x+1\right)^2} \, dx[/tex]

can, by elementary operations, be written as

[tex]a_{n}=1+\frac{1}{2^{2n}}+\frac{1}{3^{2n}}-\frac{1}{4^{2n}}+...[/tex] and so can be written with the zeta function:

[tex]a_{n}=(2-\frac{1}{2^{2(n+1)}}) \zeta(2n)[/tex]

and, [tex]\zeta(2n)=2^{2n-1}\frac{\pi^{2n}}{(2n)!}B_{n}[/tex] where B_n are the bernoulli numbers.

Well, aren't any easier way, using integration in complex plane? Can you give me an ideia of where can I find a resolution to this?

Thanks,
littlepig
 
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