Integration technique: Multiplication by a form of 1.

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SUMMARY

The discussion focuses on the integration technique of multiplying by a form of 1 to simplify trigonometric integrals, specifically using the integral \(\int \frac{d\theta}{\cos(\theta)}\). By multiplying the integrand by \(\frac{\cos(\theta)}{\cos(\theta)}\), the integral transforms into \(\int \frac{\cos(\theta)d\theta}{1 - \sin^2(\theta)}\), which can be solved through substitution \(u = \sin(\theta)\). This method effectively demonstrates how to tackle complex integrals, such as those involving secant functions, by making them more manageable through strategic manipulation.

PREREQUISITES
  • Understanding of basic integral calculus concepts
  • Familiarity with trigonometric functions and identities
  • Knowledge of substitution methods in integration
  • Experience with partial fraction decomposition
NEXT STEPS
  • Research examples of trigonometric integrals using the technique of multiplying by a form of 1
  • Study the method of substitution in integration, particularly with trigonometric functions
  • Explore partial fraction decomposition techniques for integrating rational functions
  • Practice solving integrals involving secant and cosecant functions
USEFUL FOR

Students studying calculus, mathematics educators, and anyone looking to enhance their skills in solving trigonometric integrals through innovative techniques.

Zeth
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I would much appreciate if someone could direct me to a webpage that has examples of this. My book, Thomas Calculus, only has one example (elementary) and this is for self study so I don't have lecture notes to go with it. All the questions in it are on trig integrals if that's any help.
 
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Take the simple case \int \frac{d\theta}{cos(\theta)}\

Multiply the integrand by \frac{cos(\theta)}{cos(\theta)}\, which is 1, and you get:

\int \frac{cos(\theta)d\theta}{cos^2(\theta)}\ = \int \frac{cos(\theta)d\theta}{1 - sin^2(\theta)}\

Then, if you put u = sin(\theta), and make all necessary substitutions, the integral becomes:

\frac{du}{1 - u^2}\

Which is trivial to integrate by partial fractions. So hopefully I have shown that multiplication by a form of 1 can be useful in finding integrals that look intimidating such as the integral of sec(x), as above.
 
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Oh I do know it is useful, that's why I want the practice. It's just that I wanted to get more of a feel for how it's done by some examples that are worked through. Worst comes to worst I'll just make some up and back differentiate them and see what happens then.
 

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