Integration using u substitution and arctan

  • Thread starter dante3001
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Main Question or Discussion Point

so i'm having problems with the coefficients in this problem.

[tex]\int[/tex](10z+8/z^2-8z+41)dz

i know that the main chunk is

(a)ln|(z-4)^2+25|+(b)arctan((z-4)/5)

a and b are 5 and 32/5 respectively
the problem is i can't seem to split up the top so that the first portion is the derivitive of the bottom and that the other top is the right constant.
 

Answers and Replies

(a)ln|(z-4)^2+25|+(b)arctan((z-4)/5)
If this is not the answer how it is related to the question..?:smile:
 
2
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the main part is not what i need explained which is the chunk there. it is the a and b portion. i just need to know how the coefficients are found
 
[tex]\int[/tex](10z+8/z^2-8z+41)dz
Do you mean
[tex]\int\frac{10z+8}{z^2-8z+41}dz[/tex]
?

To me it is not clear what you already solved and where your problem is. I suggest you present what you did so far and how you obtained the partial answer (a).

-Pere
 
Last edited:

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