Intensity of a sound wave problem

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The discussion revolves around calculating the ratio of maximum displacements of two loudspeakers producing different frequencies while maintaining the same intensity at a listener's position. Participants emphasize the need to use the correct equations for sound intensity and clarify the terms involved, such as intensity, pressure, angular frequency, amplitude, and density. There is confusion regarding the notation and definitions of variables in the equations, particularly the distinction between power and pressure. The importance of understanding the derivation of equations and the physical meaning behind each term is highlighted as essential for solving the problem. Overall, a deeper comprehension of sound intensity and its related equations is necessary for accurate problem-solving.
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Homework Statement



Two loudspeakers are placed beside each other and produce sound of the same intensity at the position of a listener. One speaker produces a low note of 40 Hz and the other produces a high note of 2560 Hz. What is the ratio of the maximum displacements of the speakers vibrating cones?

Homework Equations



1) I=P/4piR^2
2) I=1/2BωkA^2
3) I=1/2\sqrt{ρB}ω^2A^2

The Attempt at a Solution


I understand that I am supposed to use equation 3 for both frequencies and set them equal to each other to come up with a ratio. I just don't understand how equation 3 is derived from equation 1, or how equation 2 is derived from equation 1 for that matter. If I could see how to manipulate these equations I would understand this type of problem much better. (The only equation I am given on my equation sheet is the first one).
 
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Well what do each of the terms in the equations mean?
 
Well I is intensity of the wave, p is the pressure, r is radius, ω is angular frequency, k is 2pi/\lambda, A is amplitude, and ρ is density. Right?
 
Well I is intensity of the wave, p is the pressure, r is radius, ω is angular frequency, k is 2pi/λ, A is amplitude, and ρ is density. Right?
This is incomplete, and you have not been consistent in your notation.

Taken in order:
- Intensity of the sound wave - good;
- there is no "p" in your equations. Do you mean "P" here?
##\qquad##... sound is a pressure wave, so there are lots of pressures all over the place so which pressure does P refer to? Or is that P for "power"?
- there is no "r" in your equations, do you mean "R"? What is R the radius of?
- ##\small{\omega}## = angular frequency of the wave
##\qquad \small{\omega = vt = 2\pi f}## where v is the wave-speed and f is the frequency of the wave. ##\small{k(x-vt)=kx-\omega t}##
- ##\small{k=2\pi/\lambda}## good, it's called the wave number.
- What is A the amplitude of
##\qquad##- if "the sound wave" then is it a pressure or a displacement or something else?
- there are lots of different kinds of density - what is ##\small{\rho}## the density of?
- what is B? You missed it out.

If you don't know what the terms refer to then you won't be able to understand the equations.
I think you need to check your ideas about what sound intensity means:
http://en.wikipedia.org/wiki/Sound_intensity
... the intensity of the sound is the rate that energy is delivered to the listeners location per unit area.
Energy rate = energy per unit time = Power, so ##I=P/A## i.e. is power per unit area.
Revisit the equation list in post #1 with that in mind.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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