Interference of Two Waves (Interferometer)

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The discussion focuses on calculating the output intensity of an interferometer given an input signal characterized by power and phase components. The user derives the output power equation based on interference principles, but questions the omission of the data signal component, D(t), in their final result. They express uncertainty about the correctness of their calculations and seek clarification. The context is related to telecommunications, emphasizing the relevance of carrier frequency and data recovery. The user also references an article they authored to aid understanding of interferometric principles.
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Homework Statement



The input signal to the interferometer shown in the picture below is given by:

$$E_{\text{in}}=\sqrt{P}\exp\left(j\omega_{0}t+\frac{jD(t)\pi}{2}+j\varphi_{p}(t)\right). \tag{1}$$

##P## is the power that is received. The delay present in one arm of the interferometer is ##T_b##.

2017_09_16_15_16_26.jpg


I want to calculate the intensity/optical power at the output of the interferometer.

Homework Equations



For two waves ##\sqrt{I_{1}}\exp(j\varphi_{1})## and ##\sqrt{I_{2}}\exp(j\varphi_{2})##, the resulting interference equation is:

$$I=I_{1}-I_{2}+2\sqrt{I_{1}I_{2}}\cos\varphi \tag{2}$$

where ##d## is the delay distance, and ##\varphi = \varphi_2 - \varphi_1##.

The Attempt at a Solution



So from the interference equation:

$$P_{\text{out}}=2P\left[1+\cos\left(\frac{2\pi d}{\lambda}\right)\right]=2P\left[1+\cos\left(\frac{2\pi cT_{b}f}{c}\right)\right]$$

$$=2P\left[1+\cos\left(2\pi T_{b}f\right)\right]=2P\left[1+\cos\left(T_{b}\omega\right)\right]. \tag{3}$$

Is this correct?

The context of this problem is in telecom. ##\omega_0## represents the carrier frequency, ##D(t)## is the actual data that has to be recovered. However ##D## is absent from (3) so I am thinking that my result is probably not correct. :confused:

Any explanation would be greatly appreciated.
 
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