Interpretation of the polarizability

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SUMMARY

The discussion focuses on the interpretation of static polarizability in an electron gas using the Lindhard formula, specifically the behavior of the susceptibility function \(\chi(q)\). It establishes that \(\chi(q)\) remains nearly constant until the wave vector \(q\) reaches \(2k_F\), where \(k_F\) is the Fermi wave vector, after which it decays. The interpretation suggests that short wavelengths are not effectively screened, and for \(k < 2k_F\), static screening can be understood through Thomas-Fermi theory, while for \(k > 2k_F\), significant energy is required to alter electronic wavefunctions.

PREREQUISITES
  • Understanding of the Lindhard formula for electron gas polarizability
  • Familiarity with the concept of Fermi wave vector (\(k_F\))
  • Knowledge of Thomas-Fermi theory
  • Basic principles of perturbation theory in quantum mechanics
NEXT STEPS
  • Study the Lindhard formula in detail to understand its applications
  • Explore the implications of Fermi wave vector (\(k_F\)) in solid-state physics
  • Investigate Thomas-Fermi theory and its relevance to screening effects
  • Learn about perturbation theory and its role in modifying electronic wavefunctions
USEFUL FOR

This discussion is beneficial for physicists, particularly those specializing in condensed matter physics, as well as students and researchers interested in electron gas behavior and screening phenomena.

daudaudaudau
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Hello!

If one uses the Lindhard formula to calculate the static polarizability of an electron gas, [itex]\chi(q)[/itex], you get a function which is pretty much a constant until [itex]q=2k_F[/itex] with [itex]k_F[/itex] being the Fermi wave vector. After this it decays(it's on page 335 of Ashcroft and Mermin). But what is the interpretation of this? Somehow short wavelengths are not screened very well?
 
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For k<2k_K, you can understand static screening in therms of Thomas-Fermi theory, i.e. the external potential modifies the local Fermi Energy and the filling of the orbitals, in terms of perturbation theory, you work with zeroth order wavefunctions and change only occupation, due to the degeneracy of the electron gas, this costs little energy. For higher values of k >2k_F, you really have to bend the electronic wavefunctions which costs more energy (I would guess of the order of min(k-2k_F)*k_F/m=min(k-2k_F)*v_F).
 

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