Interpretation of the Weinberg-Witten theorem

In summary: Ricci-flat, not to be Minkowskian. From asymptotic safety we know that quantizing perturbative gravitons is wrong, whereas an UV completion might be possible but not with the usual perturbative Graviton / not with a Gaussian fixed Point. In LQG there are no Gravitons at all, but it's possible to derive an approximation with an IR graviton propagator.That means in neither theory Poincare invariance relevant - as far as I can see.In summary, the Weinberg-Witten theorem states that a 3+1D QFT with a conserved 4-vector current and stress-energy tensor, both Poincare covariant, cannot have mass
  • #1
Afonso Campos
29
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The Weinberg-Witten theorem (https://en.wikipedia.org/wiki/Weinberg–Witten_theorem) states that

A ##3 + 1##D QFT quantum field theory with a conserved ##4##-vector current ##J^\mu## which is Poincaré covariant does not admit massless particles with helicity ##|h| > 1/2##.

A ##3 + 1##D QFT with a conserved stress–energy tensor ##T^{\mu \nu}## which is Poincaré covariant does not admit massless particles with helicity ##|h| > 1##.

This theorem is interpreted to mean that the graviton cannot be a composite particle. However, I do not quite follow this interpretation.

My understanding is that the massless graviton of spin ##2## ought to have a Poincare-covariant conserved stress-tensor (and Poincare-covariant conserved ##4##-vector currents associated to other symmetries). So the Weinberg-Witten theorem means the graviton is not allowed to exist at all.

That the graviton is not allowed to be a composite particle appears to be a weaker conclusion.
 
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  • #3
atyy said:
In contrast to the classical graviton, the quantum graviton does not has a Poincare-covariant conserved stress-tensor. There is a discussion about this around Eq 4.19 in Loebbert's essay about the Weinberg-Witten theorem: http://onlinelibrary.wiley.com/doi/10.1002/andp.200810305/abstract.

what about composite gravitons?
 
  • #4
kodama said:
what about composite gravitons?

The original paper states exceptions, eg. Sakharov gravity.
 
  • #5
atyy said:
The original paper states exceptions, eg. Sakharov gravity.

does WW rule out the possibility gravitons are not fundamental but emergent quasiparticles?
 
  • #6
kodama said:
does WW rule out the possibility gravitons are not fundamental but emergent quasiparticles?

Yes, under the conditions of the theorem. For example, string theory is able to have gravitons that are not fundamental,but are emergent quasiparticles.
 
  • #7
atyy said:
In contrast to the classical graviton, the quantum graviton does not has a Poincare-covariant conserved stress-tensor. There is a discussion about this around Eq 4.19 in Loebbert's essay about the Weinberg-Witten theorem: http://onlinelibrary.wiley.com/doi/10.1002/andp.200810305/abstract.

what's the difference between a classical graviton and the quantum graviton?

aren't all gravitons quantum bosons?
 
  • #8
The perspective of the theorem is a graviton on flat, classical Minkowski background with Poincare symmetry, i.e. perturbative gravity. This approach has many other issues, especially perturbative non-renormalizability.

In quantum gravity I would not introduce any background but quantize spacetime as a whole. So there is no background, no QFT on this background and no Poincare invariance at all, which means that the theorem does not apply. In many theories like strings, loop quantum gravity, geometrodynamics with asymptotic safety there isn't even the idea of a fundamental or perturbative graviton, which means the theorem is pointless. It does not affect any theory on quantum gravity I am aware of (the situation nay have been different in 1980)
 
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  • #9
tom.stoer said:
The perspective of the theorem is a graviton on flat, classical Minkowski background with Poincare symmetry, i.e. perturbative gravity. This approach has many other issues, especially perturbative non-renormalizability.

In quantum gravity I would not introduce any background but quantize spacetime as a whole. So there is no background, no QFT on this background and no Poincare invariance at all, which means that the theorem does not apply. In many theories like strings, loop quantum gravity, geometrodynamics with asymptotic safety there isn't even the idea of a fundamental or perturbative graviton, which means the theorem is pointless. It does not affect any theory on quantum gravity I am aware of (the situation nay have been different in 1980)

In QM there is the wave-particule duality. Since there are gravitational waves, what is the corresponding particle via duality in quantize spacetime , loop quantum gravity, geometrodynamics
 
  • #10
kodama said:
In QM there is the wave-particule duality. Since there are gravitational waves, what is the corresponding particle via duality in quantize spacetime , loop quantum gravity, geometrodynamics
Why is there wave-particle duality in quantum gravity? How shall we know? Why is it the correct way to quantize gravitational waves to get gravitons?

Quantizing water waves does not result in H20 molecules, either.

From all what we know it could be the other way round.

In starting with gravitational waves is not like string theory works; gravitons are approximations in a certain regime; background spacetime is restricted to be Ricci-flat, not to be Minkowskian. From asymptotic safety we know that quantizing perturbative gravitons is wrong, whereas an UV completion might be possible but not with the usual perturbative Graviton / not with a Gaussian fixed Point. In LQG there are no Gravitons at all, but it's possible to derive an approximation with an IR graviton propagator.

That means in neither theory Poincare invariance relevant - as far as I can see.
 
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  • #11
tom.stoer said:
Why is there wave-particle duality in quantum gravity? How shall we know? Why is it the correct way to quantize gravitational waves to get gravitons?

Quantizing water waves does not result in H20 molecules, either.

From all what we know it could be the other way round.

In starting with gravitational waves is not like string theory works; gravitons are approximations in a certain regime; background spacetime is restricted to be Ricci-flat, not to be Minkowskian. From asymptotic safety we know that quantizing perturbative gravitons is wrong, whereas an UV completion might be possible but not with the usual perturbative Graviton / not with a Gaussian fixed Point. In LQG there are no Gravitons at all, but it's possible to derive an approximation with an IR graviton propagator.

That means in neither theory Poincare invariance relevant - as far as I can see.

quantizing sound waves gives rise to phonons. i have wondered if gravitons are not a fundamental particle but an emergent particle like phonons and how this would affect physics. so the only fundamental bosons are spin0 and spin1
 
  • #12
kodama said:
quantizing sound waves gives rise to phonons
Yes, but there are two main differences: phonons are well-defined mathematically (when respecting the lattice cut-off), and they do work in practice, whereas perturbative gravitons neither result in a well-defined theory, nor are required by observations.

kodama said:
i have wondered if gravitons are not a fundamental particle but an emergent particle like phonons and how this would affect physics. so the only fundamental bosons are spin0 and spin1
I am no so sure what this could mean. Looking at LQG there is nothing like a particle at all. Looking at the asymptotic safety scenario there is a spin-2 field in the path integral, but no perturbative graviton. So somehow QG seems to be very different from QFT.
 
  • #13
tom.stoer said:
Yes, but there are two main differences: phonons are well-defined mathematically (when respecting the lattice cut-off), and they do work in practice, whereas perturbative gravitons neither result in a well-defined theory, nor are required by observations.

perhaps gravitons need to be defined in terms of a lattice cut-off. ?

tom.stoer said:
I am no so sure what this could mean. Looking at LQG there is nothing like a particle at all. Looking at the asymptotic safety scenario there is a spin-2 field in the path integral, but no perturbative graviton. So somehow QG seems to be very different from QFT.

Rovelli though did compute 2-graviton for LQG.

any chance you can take a look at this?

Einstein Equation from Covariant Loop Quantum Gravity and Semiclassical Continuum Limit
Muxin Han
(Submitted on 25 May 2017)
In this paper we explain how 4-dimensional general relativity and in particular, the Einstein equation, emerge from the spinfoam amplitude in loop quantum gravity. We propose a new limit which couples both the semiclassical limit and continuum limit of spinfoam amplitudes. The continuum Einstein equation emerges in this limit. Solutions of Einstein equation can be approached by dominant configurations in spinfoam amplitudes. A running scale is naturally associated to the sequence of refined triangulations. The continuum limit corresponds to the infrared limit of the running scale. An important ingredient in the derivation is a regularization for the sum over spins, which is necessary for the semiclassical continuum limit. We also explain in this paper the role played by the so-called flatness in spinfoam formulation, and how to take advantage of it.

https://arxiv.org/abs/1705.09030
https://arxiv.org/abs/1705.09030
does the paper succeed in its stated aims?
 
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What is the Weinberg-Witten theorem?

The Weinberg-Witten theorem, also known as the CPT theorem, states that any relativistic quantum field theory with a stable vacuum must obey certain symmetry principles, including charge conjugation (C), parity (P), and time reversal (T), and the combination of these (CPT).

What does the Weinberg-Witten theorem imply?

The Weinberg-Witten theorem implies that particles and their antiparticles must have the same mass and spin, and that the laws of physics must be the same for particles moving forward in time as for antiparticles moving backward in time. It also places constraints on the possible interactions between particles and fields.

How is the Weinberg-Witten theorem related to the Standard Model of particle physics?

The Weinberg-Witten theorem is a fundamental result in particle physics and provides a theoretical basis for the symmetries observed in the Standard Model. It also helps to explain why there are equal numbers of particles and antiparticles in the universe.

What are the implications of the Weinberg-Witten theorem for the search for new physics?

The Weinberg-Witten theorem is a powerful tool for guiding the search for new physics beyond the Standard Model. Any proposed theories or models must be consistent with the symmetries and principles of the Weinberg-Witten theorem in order to be considered valid.

How has the Weinberg-Witten theorem been tested and confirmed?

The Weinberg-Witten theorem has been extensively tested and confirmed through numerous experiments in particle physics, including studies of particle-antiparticle interactions, measurements of particle properties, and observations of particle decays. The consistency of the predictions of the Standard Model with experimental results serves as strong evidence for the validity of the Weinberg-Witten theorem.

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