Interpretation Schrödinger's formulae

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Homework Help Overview

The discussion revolves around the interpretation of Schrödinger's formulae, specifically the terms involving wavefunctions and probability currents in quantum mechanics.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants explore the meaning of terms like \(\Psi \nabla \Psi^*\) and \(\Psi^* \nabla \Psi\), questioning their representation in reality. Some discuss the concept of probability current and its relation to classical velocity, while others inquire about empirical validation of these formulae.

Discussion Status

There is an ongoing exploration of the concepts, with some participants providing clarifications about the probability current and its implications. Questions about empirical verification and the relationship between quantum mechanics and classical concepts are being raised, indicating a productive dialogue.

Contextual Notes

Some participants express uncertainty about the basic nature of the concepts discussed, while others challenge assumptions regarding the measurement of quantum phenomena.

Raparicio
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Dear Friends,

Does anybodi knows the meaning, or anything related to the term:

\Psi \nabla \Psi^*

or

\Psi \nabla \Psi^* - \Psi^* \nabla \Psi

Is the representation of something in the reality?

Best reggards.
 
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If you have a particle having a wavefunction \psi(\vec r, t), then:

\vec J(\vec r,t)=\frac{\hbar}{2mi}(\psi^* \nabla \psi-\psi\nabla \psi^*)

is the so-called probability current. It represents the flow of probability density, like electrical current is the flow of charge density.
 
Spinor?

Galileo said:
If you have a particle having a wavefunction \psi(\vec r, t), then:

\vec J(\vec r,t)=\frac{\hbar}{2mi}(\psi^* \nabla \psi-\psi\nabla \psi^*)

is the so-called probability current. It represents the flow of probability density, like electrical current is the flow of charge density.


Thanks, Galileo, but I'm trying to "imagine" what is, for example, one of the 2 terms:

\psi^* \nabla \psi

Has it any meaning? Is a rotor of the nabla operator?

:smile:
 
Nope,it's just the ~ to the integral nucleus of the momentum operator.

Daniel.
 
Galileo said:
If you have a particle having a wavefunction \psi(\vec r, t), then:

\vec J(\vec r,t)=\frac{\hbar}{2mi}(\psi^* \nabla \psi-\psi\nabla \psi^*)

is the so-called probability current. It represents the flow of probability density.

Sorry if this is really basic, I'm no quantum guru yet :-p, but could you say that the (classical) velocity is in the direction where \vec J has global max at a given t? Is it possible somehow to calculate \vec v from \vec J?
 
Last edited:
"(Classical) velocity" has nothing to do with the probability current density...

Daniel.
 
empirical

empirical experiments verify this formulae is ok?
 
Which formulae...?We can't measure \vec{j}\left(\vec{r},t\right),but only probabilities.

Daniel.
 
Chr

dextercioby said:
Which formulae...?We can't measure \vec{j}\left(\vec{r},t\right),but only probabilities.

Daniel.

Daniel,

I mean that if exists any experiment or example in real word that confirms that formula or some of its components. For example, if the probability to find a particle in some place or time has this formula...
 
  • #10
I'm not an experimentalist and never will be,but i can assure that this simple part of QM has been fully checked and confirmed.We can't measure certain abstract things.Since QM is a probabilistic theory,all we can do is statistics.

Daniel.
 
  • #11
dextercioby said:
I'm not an experimentalist and never will be,but i can assure that this simple part of QM has been fully checked and confirmed.We can't measure certain abstract things.Since QM is a probabilistic theory,all we can do is statistics.

Daniel.

tks Daniel.
 

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