Interpreting Curl in Vector Fields: ∇×v

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In a river, the varying flow speeds create a non-zero curl, indicating rotational movement in the vector field. The expression Curl{v} = ∇×v represents this rotation, but interpreting it geometrically can be challenging. Unlike scalar fields where the gradient indicates maximum increase, the curl in vector fields measures the circulation around a loop. The direction of the curl corresponds to maximizing the line integral around a small planar loop. This concept parallels divergence, which measures net flow out of a closed surface.
Titan97
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In a river, water flows faster in the middle and slower near the banks of the river and hence, if I placed a twig, it would rotate and hence, the vector field has non-zero Curl.
Curl{v}=∇×v
But I am finding it difficult to interpret the above expression geometrically. In scalar fields, the gradient points along the direction of maximum increase. But what's the direction of gradient in a vector field? And why does the cross product give the Curl?
 
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It is not a cross product, it simply happens to have a similar form in Cartesian coordinates.

You can think of (the inner product of) the curl (with a normal to the plane) as being a measure of the line integral around a small planar loop. The direction of the curl is the direction which will maximise this line integral.

This is analogous to how you may see divergence as a measure of the net flow out of the closed surface surrounding a small volume.
 
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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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