Intersection of A & B: Answer to Puzzling Question

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Homework Help Overview

The problem involves two sets, A and B, where Set A has twice the number of elements as Set B, and one-third of the elements of Set A are also in Set B. The total number of elements in the union of A and B is given as 42, and the task is to determine the intersection of the two sets.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using the inclusion-exclusion principle to relate the sizes of the sets and their intersection. There are attempts to set up equations based on the given relationships between the sets. Some participants express confusion about the results obtained, questioning the validity of their calculations.

Discussion Status

There is ongoing exploration of the problem, with participants sharing their attempts and questioning their reasoning. Some guidance has been offered regarding potential errors in calculations, but no consensus has been reached on the correct approach or solution.

Contextual Notes

Participants note that this problem was part of an exam, and there is an emphasis on understanding the relationships between the sets rather than simply finding the answer. There are indications of elementary mistakes in calculations that have been acknowledged by some participants.

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Homework Statement


Set A has twice the number of elements as Set B, 1/3 of the elements of Set A are the same as in Set B, the union of A and B is 42, what is the intersection?

The Attempt at a Solution



This was one of my exam questions, and I just want to see what the correct answer was. What I tried to do was
use the inclusion exclusion principle so

|AUB| = |A| + |B| - (1/3)*|A|
42 = |A| + 1/2|A| - (1/3)|A|
42 = (1/6)|A| + (3/6)*|A| - (2/6)*|A|
42 = (1/3)|A|

And 42 is the intersection, but that makes absolutely no sense, can anyone show me the correct way to get the answer?
 
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Panphobia said:

Homework Statement


Set A has twice the number of elements as Set B, 1/3 of the elements of Set A are the same as in Set B, the union of A and B is 42, what is the intersection?

The Attempt at a Solution



This was one of my exam questions, and I just want to see what the correct answer was. What I tried to do was
use the inclusion exclusion principle so

|AUB| = |A| + |B| - (1/3)*|A|
42 = |A| + 1/2|A| - (1/3)|A|
42 = (1/6)|A| + (3/6)*|A| - (2/6)*|A|
42 = (1/3)|A|

And 42 is the intersection, but that makes absolutely no sense, can anyone show me the correct way to get the answer?
$$42 = |A \cup B| = |A| + |B| - |A \cap B| = 2|B| + |B| - (1/3)\underbrace{(2 |B|)}_{|A|} = (3 - 2/3) |B| = (7/3) |B|$$.
 
Panphobia said:

Homework Statement


Set A has twice the number of elements as Set B, 1/3 of the elements of Set A are the same as in Set B, the union of A and B is 42, what is the intersection?

The Attempt at a Solution



This was one of my exam questions, and I just want to see what the correct answer was. What I tried to do was
use the inclusion exclusion principle so

|AUB| = |A| + |B| - (1/3)*|A|
42 = |A| + 1/2|A| - (1/3)|A|
42 = (1/6)|A| + (3/6)*|A| - (2/6)*|A|
42 = (1/3)|A|

And 42 is the intersection, but that makes absolutely no sense, can anyone show me the correct way to get the answer?

I think if you had added 1+1/2-1/3 correctly you would have had it.
 
Wow elementary math mistakes everywhere haha, yea my mistake. I got it now.
 

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