Intersection of line and plane

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Homework Statement



Find the equation of the plane which passes through the line [itex]\frac{x-2}{3}=\frac{y-3}{1}=\frac{z+1}{2}[/itex]
and it is normal to the plane x+4yy-3z+7=0

Homework Equations





The Attempt at a Solution



I find the intersection point of the plane and the line. It is M(2,3,-1). Also I got the condition (A,B,C)(3,1,2)=0

[tex]\left\{\begin{matrix}<br /> 2A+3B-C+D=0 & \\ <br /> A+4B-3C=0 & <br /> \end{matrix}\right.[/tex]

What is the third condition ?
 
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Sorry I must fix something. Up in there is x+4y-3z+7=0, and (A,B,C)(1,4,-3)=0.
 
Is (A,B,C)(3,1,2)=0 the third condition?