Finding the Gravitational Interaction
To start with, I'll be talking about gravity. As is known, gravity is an attractive force between two masses. It's proportional to each of their masses, and inversely proportional to the square of the distance between the two objects.
Gravity is also proportional to some proportionality constant, "G", known as the Gravitational Constant.
In the form of an equation, we have:
[tex](1.1): F_{g} = \frac{-G M_{i} M_{j}}{r^{2}}[/tex]
Equation 1.1 is easily extended to normal, 3D space through the use of vectors:
[tex](1.2): \vec{F_{g}} = \frac{-G M_{i} M_{j}}{r^{2}} \hat{r_i}[/tex]
Where the vector r in equation 1.2 is:
[tex](1.3): \vec{r} = \vec{r_{i}} - \vec{r_{j}}[/tex]
And the scalar r is the usual length or norm of the vector r:
[tex](1.4): r = |\vec{r}| = \sqrt{r_{x}^{2} + r_{y}^{2} + r_{z}^{2}}[/tex]
And finally, the unit vector r-hat is simply vector r normalized to length 1:
[tex](1.5): \hat{r} = \frac{\vec{r}}{|\vec{r}|}[/tex]
But how is this useful at all? Recall Newton's second law, which states that the force exerted on an object is equal to it's mass times the acceleration:
[tex](1.6): \vec{F} = m \vec{a}[/tex]
By equating equations 1.2 and 1.6, we find:
[tex](1.7): \vec{F} = m \vec{a} = \frac{-G M_{i} M_{j}}{r^{2}} \hat{r}[/tex]
If we take the left hand side to be force on object i, then we simply have:
[tex](1.8): M_{i} \vec{a_{i}} = \frac{-G M_{i} M_{j}}{r^{2}} \hat{r}[/tex]
[tex](1.9): \vec{a_{i}} = \frac{-G M_{j}}{r^{2}} \hat{r}[/tex]
But how about the force on object j? To do so, we invoke Newton's third law: Every force has an equal and opposite force:
[tex](1.10): \vec{F_{i}} = -\vec{F_{j}}[/tex]
Using equation 1.10, we have:
[tex](1.11): \vec{F_{j}} = \frac{G M{i} M{j}}{r^{2}} \hat{r}[/tex]
We can make the attractive nature of gravity more explicit by adding the subscripts i and j. By defining the vector relationship for any vector V:
[tex](1.12): \vec{V_{ji}} = \vec{V_{i}} - \vec{V_{j}}[/tex]
We can rewrite equation 1.2, the force of object j on object i, as:
[tex](1.13): \vec{F_{ji}} = \frac{-G M{i} M{j}}{r_{ji}^2} \hat{r_{ji}}[/tex]
And the reciprocal force, in equation 1.10 as:
[tex](1.14): \vec{F_{ij}} = \frac{-G M{i} M{j}}{r_{ij}^2} \hat{r_{ij}}[/tex]