1. The problem statement, all variables and given/known data use the concept that y = c, -inf < x < inf is a constant function if and only if y' = 0 to determine whether the specified differential equation has any constant solutions: y'' + 4y' + 6y = 10 3. The attempt at a solution What throws me off in this particular problem is y''. If y' = 0 then y'' = 0 as well. Only now when I integrate y'' to y' its y' = c1 so c1 = 0 and y' still = 0. then I basically substitute my results in the equation to get: (0) + 4(0) + 6(c) = 10 6c = 10 [c = 10/6, c1 = 0] are the constant solutions to the equation. Does this make sense? Thanks.