[IntroNumTheory] Determining the remainder by using congruence

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The discussion focuses on using congruences to determine the remainder of \(453^{234} \mod 100\). The user applies the Congruence Power property, simplifying the problem to \(53^{234} \mod 100\) and further to \(9^{117} \mod 100\). The user encounters difficulty in calculating \(3^{234} \mod 100\) and seeks assistance in finding a more efficient method to compute this value, suggesting the use of calculators or spreadsheets for modular exponentiation.

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Leo Liu
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I need to use the congruence to solve this question. My strategy is to write the question as a congruence and then simplify the congruence so that I can apply Congruence to remainder to get the remainder. My work is as follows:
We know that
##453\equiv 53 (mod\, 100)##
Thus,
##453^{234}\equiv 53^{234} (mod\, 100)## by Congruence Power.
Also since
##53^2\equiv 9 (mod\, 100)##,
##53^234\equiv 9^{117} (mod\, 100)##.
So by the transitivity property, we have
##453^{234}\equiv 3^{234} (mod\, 100)##
But I am stuck here. Can someone help me out, please?
 
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Why not do powers of 3 on a calculator (or better on a spreadsheet) until something low modulo 100 appears?
 
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