Intuition about simplifying this expression

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SUMMARY

The expression (1 - e^{-t}) / (1 - e^{t}) simplifies to -e^{-t}. The discussion highlights the importance of recognizing algebraic simplifications to avoid cumbersome methods like the quotient rule for derivatives. A suggested technique for simplification involves substituting y = e^{t}, transforming the expression into a more manageable form. This approach aids in identifying potential simplifications that may not be immediately obvious.

PREREQUISITES
  • Understanding of exponential functions and their properties
  • Familiarity with algebraic manipulation techniques
  • Knowledge of the quotient rule in calculus
  • Basic skills in recognizing algebraic identities, such as the difference of squares
NEXT STEPS
  • Practice simplifying complex fractions in algebra
  • Study substitution methods in algebra to facilitate simplification
  • Learn about exponential function derivatives and their applications
  • Explore advanced algebraic identities and their proofs
USEFUL FOR

Students in mathematics, particularly those studying calculus and algebra, as well as educators seeking to enhance their teaching methods in simplifying expressions.

Ikari
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Homework Statement


I was solving a problem and came to a part where I was dealing with the expression,

1 - e-t
--------
1 - et

It turns out that this can be simplified to -e-t but I had no idea from simply looking at the first expression that it could be simplified, and I tried to continue using a cludgy quotient rule to get the derivative, where if I had have simplified it, it would have been much easier. Is this simply a matter of being inexperienced, or am I missing some concept in elementary algebra that would let me recognize a potential simplification? For instance, I can easily recognize difference of squares, etc, but not something like this. How can I become a stronger mathematician moving forward in this regard?

Thanks in advance!

Homework Equations


N/A

The Attempt at a Solution


N/A[/B]
 
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Ikari said:

Homework Statement


I was solving a problem and came to a part where I was dealing with the expression,

1 - e-t
--------
1 - et

It turns out that this can be simplified to -e-t but I had no idea from simply looking at the first expression that it could be simplified, and I tried to continue using a cludgy quotient rule to get the derivative, where if I had have simplified it, it would have been much easier. Is this simply a matter of being inexperienced, or am I missing some concept in elementary algebra that would let me recognize a potential simplification? For instance, I can easily recognize difference of squares, etc, but not something like this. How can I become a stronger mathematician moving forward in this regard?

Thanks in advance!

Homework Equations


N/A

The Attempt at a Solution


N/A[/B]
Don't beat yourself up about this. We all have cases where the answer seems obvious after we see what it is.
 
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Ikari said:

Homework Statement


I was solving a problem and came to a part where I was dealing with the expression,

1 - e-t
--------
1 - et

It turns out that this can be simplified to -e-t but I had no idea from simply looking at the first expression that it could be simplified, and I tried to continue using a cludgy quotient rule to get the derivative, where if I had have simplified it, it would have been much easier. Is this simply a matter of being inexperienced, or am I missing some concept in elementary algebra that would let me recognize a potential simplification? For instance, I can easily recognize difference of squares, etc, but not something like this. How can I become a stronger mathematician moving forward in this regard?

Thanks in advance!

Homework Equations


N/A

The Attempt at a Solution


N/A[/B]

Sometimes it helps to change the symbols: let ##y = e^t##. Then your fraction is
$$ \text{fraction} = \frac{1 - \frac 1 y}{1-y} = \frac{ \frac{y-1}{y}}{1-y}.$$
Can you see now how the simplification would proceed?

Anyway, after simplifying, put back ##e^t## in place of ##y,## (or ##e^{-t}## in place of ##1/y##).
 
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