Simplifying an expression involving complex exponentials

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SUMMARY

The discussion focuses on simplifying the expression involving complex exponentials, specifically the sum \(\sum_{ \alpha_1 + \cdots + \alpha_n = k} e^{i(\alpha_1 \theta_1 + \cdots + \alpha_n \theta_n)}\). The key approach involves expanding the sum into a traditional form with \(n-1\) sums, allowing for the last \(\alpha_n\) to be expressed in terms of \(k\) and the other \(\alpha_j\). The simplification process requires applying geometric series repeatedly to achieve a more manageable expression. This technique is particularly relevant in the context of determining characters of irreducible representations (irreps) of SU(n).

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  • Understanding of complex exponentials and their properties
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  • Knowledge of geometric series and their applications
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jgens
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Homework Statement



Simplify the following expression:
<br /> \sum_{ \alpha_1 + \cdots + \alpha_n = k} e^{i(\alpha_1 \theta_1 + \cdots + \alpha_n \theta_n)}<br />

Homework Equations



\alpha_n = k - \sum_{j=1}^{n-1} \alpha_j
0 = \sum_{j=1}^{n} \theta_j

The Attempt at a Solution



I am trying to simplify the expression above into something a little more manageable. This expression comes from determining the characters of irreps of SU(n), so if that gives anyone ideas on how to simplify this, then any advice would be much appreciated.
 
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I guess the first step I would do is to expand the sum of states over all allowed values of {α12,...}. So instead of having 1 sum, try writing it in the "traditional" form with n-1 sums;
\sum_{\alpha_1 = 0}^k \sum_{\alpha_2 = ...} ... \sum_{\alpha_{n-1} = ...}
There's no sum over the last alpha because you already know it's value.

Then "all" you need to do is to do geometric series over and over again.
 

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