Intuition behind centre of mass equation for a rigid body

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SUMMARY

The discussion centers on the understanding of the centre of mass equation for a rigid body, specifically how integrals relate to mass distribution and displacement. Participants clarify that the integral represents an element of mass multiplied by its displacement from the origin, rather than a uniform distribution. The conversation emphasizes the generality of the equation, countering the misconception that it only applies to uniform distributions.

PREREQUISITES
  • Understanding of integral calculus, specifically the concept of summation and limits.
  • Familiarity with the concept of mass distribution in physics.
  • Basic knowledge of rigid body dynamics.
  • Comprehension of displacement and its role in physics equations.
NEXT STEPS
  • Study the application of integrals in calculating the centre of mass for various shapes.
  • Explore the differences between uniform and non-uniform mass distributions.
  • Learn about the principles of rigid body dynamics in physics.
  • Investigate advanced topics in integral calculus, such as multiple integrals and their applications in physics.
USEFUL FOR

Students of physics, educators teaching dynamics, and anyone interested in the mathematical foundations of mass distribution and centre of mass calculations.

Pochen Liu
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Homework Statement
I don't understand how we move from the discrete equation to the continuous one
Relevant Equations
I don't know how to type this in
So my basic understanding of an integral is that it finds the area underneath a graph.

I understand the idea behind an integral being the summation of f(x) * delta x, where delta x approaches zero.

241461


If I look at the integral it's telling me that there's a change in mass that is being multiplied by its displacement?
Supposedly it's meant to represent a uniform distribution but I can't see it. If someone could clear up my intuition behind this that would be great :)
 
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Pochen Liu said:
change in mass that is being multiplied by its displacement?
No, it is an element of mass multiplied by its displacement from the origin.

Pochen Liu said:
it's meant to represent a uniform distribution
No, it is quite general.
 

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