Intuitive ways to think of integration and second derivative

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SUMMARY

This discussion focuses on developing an intuitive understanding of calculus concepts, specifically the definite integral and the second derivative. The definite integral is defined as the limit of a sum of area elements, which can be visualized as the area under a curve represented by rectangles. The first derivative indicates the slope of a function, while the second derivative reveals the concavity of the function, indicating whether the rate of change is increasing or decreasing. Participants share resources, including videos and textbooks, to enhance comprehension of these concepts.

PREREQUISITES
  • Understanding of basic calculus concepts, including derivatives and integrals.
  • Familiarity with the Riemann integral and its definition.
  • Knowledge of graphical representations of functions and their slopes.
  • Basic physics concepts related to vectors and their applications.
NEXT STEPS
  • Explore visual resources on the Riemann integral to solidify understanding of area under curves.
  • Study the relationship between first and second derivatives through graphical analysis.
  • Watch intuitive calculus videos on platforms like YouTube to reinforce concepts.
  • Read recommended calculus textbooks for rigorous explanations of integration and differentiation.
USEFUL FOR

Students, educators, and anyone seeking to deepen their understanding of calculus, particularly those struggling with the concepts of integration and derivatives.

Maddie1609
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Hi,

I feel sometimes when I'm doing calculus I lose the logic and intuition behind what I'm doing, especially when integrating. I have yet to find a way to think about it in a way it makes sense to me why the definite integral would tell us the area under a curve. Same with why the second derivative would show the concavity. Does anyone have a good explanation, video or book that could help me think about it more intuitively? I don't like just applying methods without knowing what I'm actually doing:smile:
 
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One definition of the integral is the sum of very small rectangles having width (dx) and height f(x). Using the rectangle definition, the area is the most intuitive understanding of a height times the width.
## \int_a^b f(x) dx = \lim_{dx \to 0} \sum_{j=0}^N f(x_j) * dx, \, N = (b-a)/dx, \, x_j = a + j*dx ##
Of course there are other definitions of integrals, but this is a pretty commonly used one.

For the derivative, is it intuitive enough to think of the first derivative as the slope?
If so, the second derivative is the slope of the slope.
If the first derivative is positive, the function is going up. If the second derivative is also positive, the rate at which the function is going up is also increasing. This gives a concave-up type function.
If the first derivative is positive and the second derivative is negative, the rate at which the function is going up is decreasing. This give a concave-down shape to the graph of the function.

I will look around for some visuals that make these points clearer.
 
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Maddie1609 said:
Hi,

I feel sometimes when I'm doing calculus I lose the logic and intuition behind what I'm doing, especially when integrating. I have yet to find a way to think about it in a way it makes sense to me why the definite integral would tell us the area under a curve.
Just about every calculus textbook leads up to the definite integral showing a picture similar to the following.
420px-Integral_approximations.svg[1].png

(See https://en.wikipedia.org/wiki/Integral)
The textbooks usually define the Riemann integral as the limit of a sum of area elements. Haven't you ever seen something like this?
Maddie1609 said:
Same with why the second derivative would show the concavity. Does anyone have a good explanation, video or book that could help me think about it more intuitively?
Do you have a feel for the meaning of the first derivative -- what it says about the graph of some function?
Maddie1609 said:
I don't like just applying methods without knowing what I'm actually doing:smile:
 
Maddie1609 said:
Hi,

I feel sometimes when I'm doing calculus I lose the logic and intuition behind what I'm doing, especially when integrating. I have yet to find a way to think about it in a way it makes sense to me why the definite integral would tell us the area under a curve. Same with why the second derivative would show the concavity. Does anyone have a good explanation, video or book that could help me think about it more intuitively? I don't like just applying methods without knowing what I'm actually doing:smile:
Hi there, Maddie.
We have the same sentiments way back my undergraduate years. I tend to solve or study things I can not realistically appreciate, thus I think of calculus as out of this world concept and certainly one of my greatest burden and hardships way back then.

Lately, I learned that is indeed a useful tool to grasp, especially dealing with sciences and engineering.

First, you need to have a mind set or convinced yourself, that calculus is not that hard - believe me this will help a lot.

Derivative is nothing but taking differences, or portions of any physical quantities (length, time, volume, mass etc.) in simple terms, on the other hand, integral or integration is just summing up all the portions on interest.

Derivative and integral comes together to provide us tools to measure lengths of a strip, surface areas, volumes (both with irregular and regular geometries).

The first derivative f'(X) of any equation or function f(x) is a function tangent to the original function . The second derivative f"(x) of function f(x) is the line(if 2d) or surface(if 3d) perpendicular to the first derivative function.
What is the importance of these? These represents the analogy of vectors (Force, Velocity, Magnetic field, etc) in physics or natural world that we could analyze them and design for use involving these parameters.
 
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I found this intuitive video (on you tube) about the definition of definite integral:



in any case I suggest a calculus book for a rigorous explanation.
 
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Relativistic Momentum, Mass, and Energy Momentum and mass (...), the classic equations for conserving momentum and energy are not adequate for the analysis of high-speed collisions. (...) The momentum of a particle moving with velocity ##v## is given by $$p=\cfrac{mv}{\sqrt{1-(v^2/c^2)}}\qquad{R-10}$$ ENERGY In relativistic mechanics, as in classic mechanics, the net force on a particle is equal to the time rate of change of the momentum of the particle. Considering one-dimensional...

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