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Inverse curves related to JFET characteristics, help

  1. May 11, 2013 #1
    Inverse curves related to JFET characteristics, help!!

    Hi,
    This is an example given in a lesson which is closely related to a coursework question I'm trying to complete, the problem is I can't understand how they have got the results they have.

    Here is the statement giving the relationship

    "The parameter rd is the small-signal drain-source resistance and can be found from the inverse of the slope of the curve of IDS against VDS at the operating point. From FIGURE 1, rd can be estimated as 12.4 kΩ at the operating point of VDS = 15 V and IDS = 10 mA."
    (figure 1 is the attached JPEG)

    I cannot understand how they have got 12.4kΩ as the value of Rd, how do I find the inverse of a curve if I have no relationship for x and y ?

    We are looking at the curve Vgs = -1

    Can any body help, I'm sure this is simple but I've been looking at it for two days now and am getting desperate.
     

    Attached Files:

  2. jcsd
  3. May 11, 2013 #2

    tiny-tim

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    Hi Trespaser5! :smile:
    The inverse of the slope is simply 1/slope.

    ie if you imagine the graph is a road, then where it goes through the point (15,10),

    you'd see a road sign saying "Gradient 1:12.4" :wink:
     
  4. May 12, 2013 #3
    Hi,
    Thanks so much for the reply and.....I think I may understand but I just want to check. I drew a tangent on the curve at that point, the took the difference in y (Ids) and divided it by x (Vds) and divided it into 1. It gave me a close answer, it also gave me a close answer to some other examples. Does this sound right to you ?
     
  5. May 12, 2013 #4

    tiny-tim

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    yup! :biggrin:

    (but, as you've probably noticed, it's not very accurate on such a small graph! :wink:)
     
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