MHB Inverse Function Theorem for One Real Variable

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The discussion revolves around the Inverse Function Theorem (IFT) for real-valued functions, specifically addressing a proof in Manfred Stoll's "Introduction to Real Analysis." A key point of confusion is the necessity of the continuity of the inverse function, f^{-1}, in the proof, particularly in establishing that f^{-1}(y_0) equals x_0. It is clarified that continuity is essential to ensure that the limit of the inverse function converges correctly. The continuity condition guarantees that the limit of sequences approaches the function's value, which is not generally true for non-continuous functions. Understanding this aspect is crucial for grasping the proof of the IFT.
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I am reading Manfred Stoll's book: Introduction to Real Analysis.

I need help with Stoll's proof of the Inverse Function Theorem (IFT) for real-valued functions of one real variable.

Stoll's statement of the IFT for Derivatives and its proof read as follows:
View attachment 3934

In the above proof we read:

" ... ... Since $$f^{-1}$$ is continuous, $$x_n \rightarrow x_0 = f^{-1} (y_0)$$ ... ... "I do not understand what Stoll means by this statement ... indeed it may be a 'typo' ... and if it is, what did he mean to say ...

Worse still for my understanding of this proof I cannot see where the continuity of $$f^{-1}$$ is required in the proof of:

$$ ( f^{-1} )' (y_0) = \frac{1}{f' (x_0 )} $$Can someone please help clarify the above situation?

Peter
 
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Hi Peter,

Continuity is needed, it's not a typo.

He tries to prove that $f^{-1}(y_0)=x_0$

For any real valued continuous (at $a$) function $h$ and any sequence $\{a_n \}_{n\in \mathbb{N}}$ with limit $a$ we got that $\underset{n \to \infty}\lim h(a_{n})=h(\underset{n \to \infty}\lim a_{n})=h(a)$, which is not true (in general) for non continuous functions (at $a$).

So he needs continuity to guarantee that $\underset{n\to \infty}\lim f^{-1}(y_{n})=f^{-1}(y_{0})$
 
Peter said:
I am reading Manfred Stoll's book: Introduction to Real Analysis.

I need help with Stoll's proof of the Inverse Function Theorem (IFT) for real-valued functions of one real variable.

Stoll's statement of the IFT for Derivatives and its proof read as follows:In the above proof we read:

" ... ... Since $$f^{-1}$$ is continuous, $$x_n \rightarrow x_0 = f^{-1} (y_0)$$ ... ... "I do not understand what Stoll means by this statement ... indeed it may be a 'typo' ... and if it is, what did he mean to say ...

Worse still for my understanding of this proof I cannot see where the continuity of $$f^{-1}$$ is required in the proof of:

$$ ( f^{-1} )' (y_0) = \frac{1}{f' (x_0 )} $$Can someone please help clarify the above situation?

Peter

Fallen Angel said:
Hi Peter,

Continuity is needed, it's not a typo.

He tries to prove that $f^{-1}(y_0)=x_0$

For any real valued continuous (at $a$) function $h$ and any sequence $\{a_n \}_{n\in \mathbb{N}}$ with limit $a$ we got that $\underset{n \to \infty}\lim h(a_{n})=h(\underset{n \to \infty}\lim a_{n})=h(a)$, which is not true (in general) for non continuous functions (at $a$).

So he needs continuity to guarantee that $\underset{n\to \infty}\lim f^{-1}(y_{n})=f^{-1}(y_{0})$
Thanks for the help, Fallen Angel ... appreciate your support ...

Peter
 

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