Inverse Solubility of Solid Solutes

Click For Summary
SUMMARY

The discussion centers on the inverse solubility of solid solutes, specifically addressing why some solids exhibit lower solubility when heated. Misha explains that the dissolution process can be exothermic, where the heat released during solute breakdown exceeds the heat required for the process. Borek emphasizes the application of Le Chatelier's principle, indicating that increasing temperature can reduce solubility for exothermic reactions while enhancing it for endothermic reactions. Additionally, the conversation touches on the solubility behavior of gases in relation to temperature.

PREREQUISITES
  • Understanding of Le Chatelier's principle
  • Knowledge of exothermic and endothermic reactions
  • Familiarity with equilibrium constants in chemical processes
  • Basic concepts of solubility and temperature effects
NEXT STEPS
  • Research the application of Le Chatelier's principle in various chemical equilibria
  • Study the temperature dependence of equilibrium constants for different solutes
  • Explore the solubility characteristics of gases in liquids at varying temperatures
  • Investigate the thermodynamics of dissolution processes for various solid solutes
USEFUL FOR

Chemistry students, educators, and professionals interested in thermodynamics, solubility principles, and chemical equilibria will benefit from this discussion.

Misha Kuznetsov
Messages
49
Reaction score
4
Why is the solubility of some solids lower when the solution is heated? I read that it is because the process is exothermic (heat from breakdown is greater than the heat needed for breakdown). But why would having extra heat from outside sources inhibit the dissolving process, wouldn't it only help it?

My source: http://www.chem.fsu.edu/chemlab/chm1046course/solubility.html

-Misha
 
Chemistry news on Phys.org
Dissolution can be speed up by the increasing temperature, but the solubility doesn't have to grow. Think in terms of Le Chatelier's principle.
 
The other thing you'll want to examine is the temperature dependence of the equilibrium constant for the solution process.
 
Misha Kuznetsov said:
Why is the solubility of some solids lower when the solution is heated? I read that it is because the process is exothermic (heat from breakdown is greater than the heat needed for breakdown). But why would having extra heat from outside sources inhibit the dissolving process, wouldn't it only help it?

My source: http://www.chem.fsu.edu/chemlab/chm1046course/solubility.html

-Misha

As Borek noted think about this in terms of Le Chatelier:

solid + H2O --> solute + heat (exothermic) ---> Increasing T will reduce solubility

solid + H2O + heat ---> solute (endothermic) --> Increasing heat will increase solubility

Interestingly, gases typically have reduced solubility in water with increasing temperature -- one reason why warm soda tastes bad...
 

Similar threads

Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
3
Views
19K
  • · Replies 23 ·
Replies
23
Views
6K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 29 ·
Replies
29
Views
12K