Investigating the Value of [itex]\omega_{c}^{ab}[itex]

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SUMMARY

The discussion centers on determining whether the component \omega_{c}^{ab} of the spin connection is zero. The key equation used is de^{a}=-\omega^{a}_{b}\wedge e^{b}, which leads to the conclusion that the antisymmetry in indices \mu and \nu implies antisymmetry in b and c. This antisymmetry is crucial for evaluating the properties of the spin connection component.

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Homework Statement



I want to know wether the component \omega_{c}^{ab}of the spin connection is zero or not?<br /> <br /> <h2>Homework Equations</h2><br /> de^{a}=-\omega^{a}_{b}\wedge e^{b}<br /> <br /> <br /> <h2>The Attempt at a Solution</h2><br /> de^{a}=-\omega^{a}_{b}\wedge e^{b}<br /> ##=-\omega^{a}_{b,\nu} e^{b}_{\mu} dx^{\nu}\wedge dx^{\mu}##<br /> ##=-\omega^{a}_{b,c} e^{b}_{[\mu}e^{c}_{\nu]} dx^{\nu}\wedge dx^{\mu}##<br /> as it is antisymmetric in ##\mu## and ##\nu##.So it is also antisymmetric in b and c.Thus one can conclude from here.
 
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m1rohit said:

Homework Statement



I want to know wether the component \omega_{c}^{ab} of the spin connection is zero or not?

Homework Equations


de^{a}=-\omega^{a}_{b}\wedge e^{b}


The Attempt at a Solution


de^{a}=-\omega^{a}_{b}\wedge e^{b}
##=-\omega^{a}_{b,\nu} e^{b}_{\mu} dx^{\nu}\wedge dx^{\mu}##
##=-\omega^{a}_{b,c} e^{b}_{[\mu}e^{c}_{\nu]} dx^{\nu}\wedge dx^{\mu}##
as it is antisymmetric in ##\mu## and ##\nu##.So it is also antisymmetric in b and c.Thus one can conclude from here.

I have reformatted your question so that the TeX commands would be visible.
 
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