Involving Landau's 'big oh' notation

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The discussion centers on Landau's 'big oh' notation, specifically the relationship between two sequences f and g, where f=O(g) indicates that there exists a constant c>0 such that |f(n)|2 leads to the conclusion that f=O(g) implies ln(f)=O(ln(g)). The argument presented shows that if |f(n)| is bounded by c|g(n)|, then ln(|f(n)|) can be expressed as ln(c) + ln(|g(n)|), provided |f(n)| and c are greater than 1 to avoid issues with logarithmic values.

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Reb
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(don't have an answer yet)

We say that two sequences f,g are f=O(g) if-f there is a c>0 such that |f(n)|<c|g(n)| uniformly as n tends to infinity.

If g(n)>2, does f=O(g) imply lnf=O(ln(g))?
 
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|f(n)| < c|g(n)| => ln(|f(n)|) < ln(c) + ln(|g(n)|). You should have |f(n)|, c > 1 to avoid problems with abs. value of logs.
 

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