Iodine and fluorine leaving group

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SUMMARY

The discussion centers on the hydrolysis rates of acyl halides in an aqueous NaOH solution, specifically comparing acyl iodides and acyl fluorides. Acyl iodides hydrolyze faster due to iodine being a superior leaving group compared to fluorine. The stability of the iodide ion, attributed to its larger size and charge dispersion, contributes to its effectiveness as a leaving group, despite fluorine's higher hydration potential. This aligns with the trend of halide acid strength increasing down the group, as evidenced by pKa values.

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  • Basic grasp of pKa values and their implications in acid strength
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jd12345
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A question in my test asked which of the acyl halide will hydrolyse faster in an aqueous solution of NaOH

Well the asnwer is acyl iodide becasue iodine is a better leaving group( the solution says so)
But i don't understand - fluorine will be hydrated to the greatest extent so removal of fluorine should be easy
 
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jd12345 said:
fluorine will be hydrated to the greatest extent so removal of fluorine should be easy

That doesn't necessarily make it more stable, though. The charge dispersion due to iodide's size makes it far more stable on its own than fluoride.

This is the same concept as halide acid strength increasing as you move down the row. Check the halide acid pKas yourself-

evans.harvard.edu/pdf/evans_pka_table.pdf
 

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