Ionic Solution Current Calculation

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Homework Help Overview

The discussion revolves around calculating the magnitude of current in an ionic solution, specifically involving the movement of positive and negative ions with different charges. The problem involves understanding the contributions of these ions to the overall current.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants express uncertainty about the appropriate equations to use for calculating current. There are attempts to calculate the current based on the flow of ions, but discrepancies in results lead to further questioning of the methodology.

Discussion Status

Some participants have provided calculations, but there is a lack of consensus on the correct approach. Questions about the underlying assumptions regarding the charge flow and the presence of multiple solutions in the electrolyte have been raised, indicating an ongoing exploration of the problem.

Contextual Notes

Participants are grappling with the implications of different charges and their contributions to the current, as well as the potential complexity introduced by having multiple solutions in the electrolyte. There is also mention of incorrect calculations, which may affect the discussion's direction.

chainsaw
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I don't even know what equation to use!

In an ionic solution, 5.0*10^15 positive ions with +2e charge pass to the right each second while 6.0*10^15 negative ions with charge -e pass to the left.

What is the magnitude of current in the solution?


(5.0*10^15)*(2*1.6*10^-19) - (6.0*10^15)*(1.6*10^-19)=8.3*10^-4
 
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Check the calculation.
 
my calculation was wrong, when I recalculated it i got 6.4E-4, and that was still wrong
What equation should i use?
 
There must be two different solutions in the electrolyte. So when +2e charge from one solution moving toward right,-2e charge is moving towards left. This adds to -e charge from the second solution. So net flow of charge is -3e towards left.
 

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