Ionic Solution Current Calculation

[chainsaw]

I don't even know what equation to use!

In an ionic solution, 5.0*10^15 positive ions with +2e charge pass to the right each second while 6.0*10^15 negative ions with charge -e pass to the left.

What is the magnitude of current in the solution?


(5.0*10^15)*(2*1.6*10^-19) - (6.0*10^15)*(1.6*10^-19)=8.3*10^-4

 

[rl.bhat]

Check the calculation.

 

[chainsaw]

my calculation was wrong, when I recalculated it i got 6.4E-4, and that was still wrong
What equation should i use?

 

[rl.bhat]

There must be two different solutions in the electrolyte. So when +2e charge from one solution moving toward right,-2e charge is moving towards left. This adds to -e charge from the second solution. So net flow of charge is -3e towards left.