Nikitin
- 734
- 27
Since acos(x) = ∫-1/√(1-x^2), and asin(x) = ∫1/√(1-x^2), won't ∫-1/√(1-x^2) = acos(x) = -1*asin(x)?
The discussion revolves around the relationship between the integral of -1/√(1-x^2) and the inverse trigonometric functions acos(x) and asin(x). Participants explore whether these expressions are equivalent, particularly in the context of integration and the constant of integration.
Participants do not reach a consensus, as there are competing views regarding the equivalence of the integrals and the implications of the constant of integration.
The discussion highlights the importance of the constant of integration in evaluating indefinite integrals, which remains unresolved in the context of the claims made.