Is 2 Really Equal to 1? A Mathematical Paradox

  • Context: High School 
  • Thread starter Thread starter Himal kharel
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Discussion Overview

The discussion revolves around a mathematical paradox questioning whether 2 can be considered equal to 1. Participants explore various proofs and reasoning, focusing on algebraic manipulations and the implications of dividing by zero.

Discussion Character

  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant presents a proof that leads to the conclusion that 2 equals 1, using algebraic manipulation starting from the assumption that a equals b.
  • Another participant critiques the proof, suggesting that dividing by zero is the source of the erroneous conclusion.
  • A third participant introduces a different argument involving complex numbers, demonstrating a similar fallacy by manipulating square roots.
  • A later reply reiterates the division error in the original proof, emphasizing the invalidity of the step where (a-b) equals zero.
  • One participant shares a link to additional examples of mathematical fallacies for further exploration.

Areas of Agreement / Disagreement

Participants do not reach a consensus; there are multiple competing views regarding the validity of the proofs and the nature of the errors involved.

Contextual Notes

Limitations include the assumption that a equals b without addressing the implications of this assumption, particularly in relation to division by zero.

Himal kharel
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let a=b
a2=ab
a2-b2=ab-b2
(a+b)(a-b)=b(a-b)
a+b=b
a+a=a<from above>
2a=a
2=1
PROVED
 
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When you divide by zero you can 'prove' all sorts of nonsense.
 
Here's another classic, using "i" as the square root of (-1).
Can you spot the error?

[tex]1=\sqrt{1}=\sqrt{((-1)*(-1))}=\sqrt{(-1)}*\sqrt{(-1)}=i*i=-1[/tex]
That is:
1=-1
 
Himal kharel said:
let a=b
a2=ab
a2-b2=ab-b2
(a+b)(a-b)=b(a-b)
a+b=b
a+a=a<from above>
2a=a
2=1
PROVED

The part in red

(a+b)(a-b)=b(a-b)

Remember we defined a=b, therefore (a-b) must equal zero. You can't divide zero as it is a division error.
 

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