Is a + b a Factor of a²(b + c) + b²(c + a) + c²(a + b) + 2abc?

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Homework Help Overview

The problem involves determining whether \( a + b \) is a factor of the expression \( a^2(b + c) + b^2(c + a) + c^2(a + b) + 2abc \). The discussion centers around polynomial factorization and the conditions under which a polynomial has a specific factor.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to rearrange the expression into a factored form rather than assuming it equals zero. There are attempts to relate the expression to polynomial properties and conditions for factors. Some participants question the original problem statement and its accuracy.

Discussion Status

The discussion is ongoing with various interpretations being explored. Some participants suggest methods for factorization, while others express confusion about the proof process. There is no explicit consensus on the approach to take, but several lines of reasoning are being examined.

Contextual Notes

Participants note the importance of understanding the definition of a factor and how it applies to the problem. There is also mention of the original poster's uncertainty regarding the proof requirements set by the teacher.

MorallyObtuse
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I tried, doubt I'm even close to correct. Show me where I went wrong or just guide me with the problem please.

Homework Statement


1.) Prove that a + b is a factor of a²(b + c) + b²(c + a) + c²(a + b) + 2abc and write down the other two factors.

2. The attempt at a solution

a^2(b - a) + b^2(-a + a) + (-a)^2(a + b) + 2ab(-a) = 0
a^2b - a^3 - b^2a + b^2a + a^2 + ab - 2ab = 0
a^2b - a^3 + a^2 - ab = 0a^2(-c + c) + (-c)^2(c +a) + c^2(a - c) + 2a(-c) = 0
-a^2c + a^2c + c^2 + ac + c^2a - c^3 - 2ac = 0
c^2 + c^2a - c^3 - ac = 0

(-b)^2(b + c) + b^2(c - b) + c^2(-b + b) + 2(-b)bc = 0
b^2 + bc + b^2c - b^3 - c^2b + c^2b - 2bc = 0
b^2 + b^2c - b^3 - bc = 0
 
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You're not given that a^2(b + c) + b^2(c + a) + c^2(a + b) + 2abc is equal to zero. All you're supposed to be doing is to rearrange what you have to put it into a factored form.

Having said that, how does the following expression relate to the expression above?
a^2(b - a) + b^2(-a + a) + (-a)^2(a + b) + 2ab(-a)

Also, are you sure that you have typed the problem exactly as it was given to you? I was able to factor the given expression into (b + c) times another factor, but I haven't been able to write it yet as (a + b) times another factor.
 
No, a+ b is a factor. Think of this as a polynomial in a with b and c constants. a+ b= a-(-b) will be a factor if and only if setting a= -b makes the polynomial equal to 0. And, of course, you can find the other factor by dividing by a+b.
 
Hi!:smile:
Solution to this is quite simple..
1st open the brackets
:. you have
a2b+ab 2+b2c+c2b+a2c+c2a+2abc
=ab(a+b) +b2c+a2c+c2b+c2a+2abc=ab(a+b)+c 2(a+b)+b2c+a2c+2abc
= (ab+c 2)(a+b)+c(b 2+a 2+2ab)
=(ab+c 2)(a+b)+c(a+b)2
=(a+b)(c2+ab+ac+bc)
That's what I think.
(there could be some mistakes while typing in powers because I kinda get confused while typing them)
I hope this helps!:smile:
 
Yes, I typed the question exactly as it was given.
I'm not sure how to 'prove'. The teacher keeps giving these proofs and I get baffled by them.
 
HallsofIvy said:
a+ b= a-(-b) will be a factor if and only if setting a= -b makes the polynomial equal to 0.

a + b = 0, and so
a = -b or b = -a
 
Last edited:
Hey what's the big deal then .
You "PROVE" it by giving the definition of factor and as it suits this condition :. You can say it is a factor of it.
See if it helps(?)
 

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