student34
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My professor actually told us that it isn't, but I don't see how it's not. If he meant that one of the stars is not in equilibrium, then that would make sense to me.
The discussion centers around the concept of equilibrium in a two-star orbiting system, particularly whether such a system can be considered in equilibrium from a force perspective. Participants explore various definitions and implications of equilibrium in the context of circular and elliptical orbits, as well as the effects of gravitational forces and reference frames.
Participants do not reach a consensus on whether the two-star system can be considered in equilibrium. Multiple competing views remain, with some arguing for equilibrium under certain conditions while others assert that unbalanced forces prevent it.
Participants note that the definition of equilibrium varies depending on the context and the specific conditions of the system, leading to unresolved questions about how to apply the term in this discussion.
Strictly, there is no equilibrium in a circular orbit but, in the reference frame of one star, the forces are balanced and distances are not changing, so ...JustinRyan said:Doesn't a circular orbit also have an acceleration? If the force between them is not constant but oscilates with a regular period, could this not be considered an equilibrium of sorts?
Student34, if you are not sure what your professor meant by this, I suggest you ask him/her.
In the inertial frame. But with circular orbits you could find a frame where both objects are in equilibrium. With elliptical orbits that is not possible.JustinRyan said:Doesn't a circular orbit also have an acceleration?
sophiecentaur said:If the orbits were circular then you 'could' argue that there is equilibrium but most orbits are elliptical, in which case there are unbalanced forces and consequent acceleration. So no.equilibrium, by definition.
student34 said:What if the system is defined to be both stars.
student34 said:What if the system is defined to be both stars; then don't the stars cancel out each other's force? Let's assume the orbits do not change in time, and assume gravitational radiation is negligible.
MikeyW said:Why would you add the forces acting on two different particles?
This sum will be zero by the definition of Newton's third law.
Please define precisely what you mean when you ask whether a multiple particle system is "in equilibrium". This question is still vague to me.
You could view the elliptic orbits as "current state" and come to a different conclusion.Using that definition, I'd say that a circular orbit would be in equilibrium but an elliptical orbit would not.
sophiecentaur said:If you were living on one of those stars (I guess it would need to be a rotating planet for this thought expt.) and it was covered in cloud, you would be aware of the other body because of the tiny tidal force as it rotated. Hence, I suppose you would be aware that you were not actually in equilibrium.
But the earlier question ("what is meant by equilibrium?") needs to be addressed if we really want closure on this.
student34 said:In terms of physics, does a mass in equilibrium mean that there are no net forces acting on it?
MikeyW said:By the definition we learnt, equilibrium = all forces cancel/no net force.
MikeyW said:It just seems very backwards to me to think of a word, then explore what it could mean. I don't see how the process could be anything but pure semantics.