- #1

Yankel

- 395

- 0

If A and B are both squared invertible matrices and A is also symmetric and:

\[AB^{-1}AA^{T}=I\]

Can I say that

\[B=A^{3}\] ?

In every iteration of the solution, I have multiplied both sides by a different matrix. At first by the inverse of A, then the inverse of the transpose, etc...Is this the correct approach to solve this ? Thank you in advance !

Another question. If A in both symmetric and invertible, it doesn't mean that the inverse of A is equal to A, right ?