Is Conditional Probability Influenced by Consecutivity

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
kashmir0109
Messages
2
Reaction score
0
What I mean by this is,
Say I roll a die, given the specific condition that I get four eights consecutively such as
"8888",
the same probability as if I give the specific condition that I get another specific non-consecutive number such as?
"0248"

OR

Say I flip a quarter. Would the probability that I get HHHH in a row, the same as if I specify beforehand to get, say, HTHH?
 
Physics news on Phys.org
I don't quite get your question. Are you asking whether the probability that you'll roll a particular sequence is dependent on what you've rolled previously? If so, the answer is no; see here,[/PLAIN] but also see the caveat here, which may be more relevant to your question.
 
Last edited by a moderator:
kashmir0109 said:
What I mean by this is,
Say I roll a die, given the specific condition that I get four eights consecutively such as
"8888",
the same probability as if I give the specific condition that I get another specific non-consecutive number such as?
"0248"

OR

Say I flip a quarter. Would the probability that I get HHHH in a row, the same as if I specify beforehand to get, say, HTHH?

The answer to the second question is yes. I suspect it also true for the first, but yuou need to describe this peculiar die - are all numbers equally probable?