Is Cos(pi(2x+1)) the Key to Simplifying the Search for x Values?

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SUMMARY

The discussion centers on the equation sec(pi(2x+1)) = 2 and its implications for simplifying the search for x values. Participants clarify the correct interpretation of the equation, confirming that sec(pi(2x+1)) = 2 is the intended expression. The transformation to cos(pi(2x+1)) is explored as a potential simplification method for solving for x. The final solution derived is x = -3/2, indicating a specific value that satisfies the equation.

PREREQUISITES
  • Understanding of trigonometric functions, specifically secant and cosine.
  • Familiarity with algebraic manipulation of equations.
  • Knowledge of solving trigonometric equations for variable isolation.
  • Basic grasp of the unit circle and its properties related to angle measures.
NEXT STEPS
  • Study the properties of secant and cosine functions in trigonometry.
  • Learn techniques for solving trigonometric equations, focusing on transformations.
  • Explore the implications of the unit circle on trigonometric identities.
  • Investigate the use of graphing calculators or software for visualizing trigonometric functions.
USEFUL FOR

Mathematics students, educators, and anyone interested in solving trigonometric equations or simplifying expressions involving secant and cosine functions.

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sec(pi)=2/2x+1
-1=2/2x+1
-2x-1=2
-2x=3
x=-3/2

is this correct?
 
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is the original supposed to be sec(pi)(2x+1) = 2?
 
sec(pi(2x+1)=2

the original
 
That doesn't make any sense. You have two "(" and only one ")".
The whole question is whether you mean sec(pi(2x+1))= 2 or sec(pi(2x)+ 1= 2 and you still haven't answered that.
 
sec(pi(2x+1))= 2 is what i mean.
 
Karma said:
sec(pi(2x+1))= 2 is what i mean.

So cos(pi(2x+1)) = ? Does that suggest an easier way to search for the values of x?
 

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