Is Delta H of formation the same for NH4NO3 Aqueous and in Solid Form?

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SUMMARY

The discussion centers on the application of Hess' Law to determine the Delta H of a reaction involving NH4NO3 in both solid and aqueous states. The user is attempting to use two specific reactions involving NH4NO3 and HCl to derive the enthalpy change for a third reaction. Key points include the importance of considering the enthalpy of solution for NH4NO3 and the clarification that solid NH4OH does not exist. The user seeks confirmation on whether the reactions can be combined using Hess' Law effectively.

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  • Understanding of Hess' Law in thermodynamics
  • Knowledge of enthalpy changes, specifically enthalpy of solution
  • Familiarity with chemical reaction equations
  • Basic principles of aqueous and solid state chemistry
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I am doing a project in Chemistry and I need to use Hess' Law to cancel two equations and if in one equation the NH4NO3 is solid and in the second one the NH4NO3 is aqueous.

The equations are:
1: NH4NO3 (s) + HCl (aq) --> HNO3 (aq) + NH4Cl (aq)
2: NH4OH (s) + HNO3 (aq) --> H2O (l) + NH4NO3 (aq)

I will find the heat of reaction for both of these reactions and use those values and Hess' law to find the Delta H of this reaction:

HCl (aq) + NH4OH (s) --> NH4Cl (aq) + H2O (l)I am wondering if these procedure will work because I created this myself for the project we are doing and I don't know:

1. Whether these individual reactions work
2. Whether they add up to the overall reaction and whether that reaction even works.

The part that is getting me stuck up is whether I can use Hess' law to cancel and aqueous version of NH4NO3 with a solid version.

Your knowledge and advice is much appreciated!
Thank you!
 
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You have to take into account the enthalpy of solution. The Wikipedia entry http://en.wikipedia.org/wiki/Enthalpy_change_of_solution lists a few values, including that for ammonium nitrate.

[Edit: I don't know why I focussed on ammonium nitrate, which is not what you asked about. See Borek's much better answer.]
 
Last edited:
No such thing as solid NH4OH.
 

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