Is E1 or E2 the Correct Mechanism for Bulky Base Eliminations?

Click For Summary

Discussion Overview

The discussion centers on the mechanisms of bulky base eliminations, specifically whether E1 or E2 is the correct mechanism in a given reaction scenario involving t-butyl alcohol and the Hoffmann elimination. Participants explore the conditions favoring each mechanism and the implications of using bulky bases.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant argues that E2 is favored due to the use of a bulky base (tBuOH) and suggests that the Hoffmann elimination leads to a major product, supporting option A.
  • Another participant counters that the bulky alcohol is unlikely to engage in E2 and emphasizes that E1 is favored in polar, non-nucleophilic solvents like t-Butanol, especially with good leaving groups.
  • There is a reiteration of the idea that bulky bases typically lead to Hoffmann elimination (E2) due to reduced crowding, although this claim is questioned.
  • A participant seeks clarification on the presence of a strong base in the example, which is critical for determining the mechanism.
  • There is a mention that Hoffmann eliminations apply specifically to quaternary alkyl amines in the presence of a strong base, prompting further inquiry into whether this applies to the current case.

Areas of Agreement / Disagreement

Participants express differing views on whether E1 or E2 is the correct mechanism, with no consensus reached. The discussion remains unresolved regarding the appropriate mechanism for the reaction in question.

Contextual Notes

Participants highlight the importance of solvent polarity, the nature of the base, and the structure of the substrate in determining the mechanism, but these factors remain under debate without definitive conclusions.

Zayan
Messages
63
Reaction score
7
Thread moved from the technical forums to the schoolwork forums
TL;DR Summary: E1 or E2? I did the E2 hoffman elimination because it's tbuOh so it's bulky hence does E2 with Hoffman as major product so I chose option A. But the solution manual has done E1 reaction and rearrangement so the answer marked is C. What is the correct mechanism?

1000018084.jpg
 
Physics news on Phys.org
The alcohol is bulky and therefore NOT likely to be engaging in E2. Hoffman elimination has a strong base. Is there a strong base in this example?

E1 is favored by a polar,non-nucleophilic solvent like t-Butanol and good leaving groups like I. This is textbook E1.
 
chemisttree said:
The alcohol is bulky and therefore NOT likely to be engaging in E2. Hoffman elimination has a strong base. Is there a strong base in this example?

E1 is favored by a polar,non-nucleophilic solvent like t-Butanol and good leaving groups like I. This is textbook E1.
I had read that bulky bases do hoffman elimination (E2) because of less crowding.
 
Where did you read that?

Hoffmann eliminations apply to quaternary alkyl amines in presence of a strong base.

Is that the case here?
 

Similar threads

  • · Replies 0 ·
Replies
0
Views
2K
Replies
13
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
8K
Replies
5
Views
4K
Replies
2
Views
4K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 28 ·
Replies
28
Views
5K
Replies
1
Views
3K
Replies
2
Views
2K