Is E1 or E2 the Correct Mechanism for Bulky Base Eliminations?

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The discussion centers on whether the elimination mechanism in question is E1 or E2, particularly in the context of a bulky base and solvent. The initial choice of E2 is challenged by the presence of t-Butanol, which favors E1 due to its polar, non-nucleophilic nature and good leaving groups. Participants note that bulky alcohols typically do not engage in E2 eliminations, reinforcing the preference for E1 in this scenario. The conversation also touches on the conditions required for Hoffmann eliminations, specifically the need for a strong base, which raises questions about its applicability in this case. Overall, the consensus leans towards E1 being the correct mechanism given the provided conditions.
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TL;DR Summary: E1 or E2? I did the E2 hoffman elimination because it's tbuOh so it's bulky hence does E2 with Hoffman as major product so I chose option A. But the solution manual has done E1 reaction and rearrangement so the answer marked is C. What is the correct mechanism?

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The alcohol is bulky and therefore NOT likely to be engaging in E2. Hoffman elimination has a strong base. Is there a strong base in this example?

E1 is favored by a polar,non-nucleophilic solvent like t-Butanol and good leaving groups like I. This is textbook E1.
 
chemisttree said:
The alcohol is bulky and therefore NOT likely to be engaging in E2. Hoffman elimination has a strong base. Is there a strong base in this example?

E1 is favored by a polar,non-nucleophilic solvent like t-Butanol and good leaving groups like I. This is textbook E1.
I had read that bulky bases do hoffman elimination (E2) because of less crowding.
 
Where did you read that?

Hoffmann eliminations apply to quaternary alkyl amines in presence of a strong base.

Is that the case here?