Is Energy Lost When a Liquid Vaporizes and Gained When a Gas Condenses?

  • Thread starter Thread starter jackcie
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on the thermodynamic principles governing the phase changes of liquids and gases, specifically vaporization and condensation. When a liquid vaporizes, the energy calculated by the formula q = m x lv is not lost but rather transformed, as dictated by the first law of thermodynamics. During vaporization, the internal energy of the gas increases due to the breaking of molecular bonds, while condensation results in heat being released as the gas transitions back to a liquid, thereby decreasing its potential energy.

PREREQUISITES
  • Understanding of the first law of thermodynamics
  • Familiarity with phase changes: vaporization and condensation
  • Knowledge of heat transfer and internal energy concepts
  • Basic principles of thermodynamic work
NEXT STEPS
  • Research the first law of thermodynamics in detail
  • Explore the concept of latent heat of vaporization (lv)
  • Study the thermodynamic properties of water during phase changes
  • Investigate the relationship between internal energy and work in gas systems
USEFUL FOR

Students of thermodynamics, physicists, and engineers interested in understanding energy transformations during phase changes in substances.

jackcie
Messages
4
Reaction score
0
when a liquid vaporises to a gas,
q = m x lv

this energy is lost?

also, what does this mean for when a gas turns to a liquid is q added to the system, or lost (added i presume??)
cheers
 
Physics news on Phys.org
jackcie said:
when a liquid vaporises to a gas,
q = m x lv

this energy is lost?
The first law of thermodynamics says that it cannot be lost: [itex]\Delta Q = \Delta U + W[/itex]. The heat flow of vaporization has to be equal to the work done by the gas plus the change in internal energy of the gas.

When water, for example, vaporizes, it expands doing work on the surrounding atmosphere. Also internal energy increases. Although the temperature of the water does not change in vaporization, the bonds between water molecules are broken in the vaporization, thereby increasing the potential energy of the gas.
also, what does this mean for when a gas turns to a liquid is q added to the system, or lost (added i presume??)
cheers
It depends on the gas. When water vapor condenses heat flows out of the gas with the loss of molecular potential energy and work is done on the gas by the surroundings as the volume decreases.

AM
 
jackcie said:
when a liquid vaporises to a gas,
q = m x lv

this energy is lost?

also, what does this mean for when a gas turns to a liquid is q added to the system, or lost (added i presume??)
cheers

(quoting the OP)
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
Replies
14
Views
1K
Replies
1
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
10
Views
3K
  • · Replies 12 ·
Replies
12
Views
7K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K