Is Every Root of 2 Higher Than 1 Irrational?

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Discussion Overview

The discussion revolves around the nature of roots of the number 2, specifically whether every root of 2 that is greater than 1 is irrational. Participants explore this concept through various types of roots, including square roots, cube roots, and higher-order roots, while considering both natural and non-natural numbers.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant suggests that the proof of the square root of 2 being irrational could be extended to other roots of 2, such as cube roots and higher-order roots, assuming these roots are natural numbers.
  • Another participant confirms the initial thought, indicating that the reasoning is valid.
  • A question is raised about proving that roots of 2 that are not natural numbers are also irrational.
  • Participants mention prime factorization as a potential method for proving irrationality.
  • The rational root theorem is also referenced as a relevant concept in the discussion.
  • One participant questions whether all roots of 2 that are not equal to 1 are irrational, leading to a clarification that the root corresponding to 1 is rational, while roots for positive integers greater than 1 are suggested to be irrational.

Areas of Agreement / Disagreement

Participants generally agree that the square root of 2 is irrational and that this property may extend to other roots of 2. However, there is no consensus on the proof for non-natural number roots or the broader implications of irrationality for all roots of 2 greater than 1.

Contextual Notes

The discussion does not resolve the mathematical steps necessary to prove the irrationality of roots beyond the square root of 2, nor does it clarify the definitions of roots being discussed.

Char. Limit
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I was thinking on the square root of 2 being irrational proof... and I got the idea that you could use the same idea for every root higher than two. The cube root, the quartic root, the quintic root, etcetera. (Obviously assuming the roots are natural numbers.)

As a reassurance I'm not crazy, is this correct?
 
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You are not crazy. At least for this particular reason. :wink:
 
Good to know.

Is there a way to prove that other roots that aren't natural numbers are irrational?
 
Prime factorization.
 
Also, rational root* theorem.

*: as in, root of a polynomial[/size]
 
So... are all roots of two that aren't 1 irrational?
 
Almost. Of course the "1" root of 2, 21/1= 2 is rational! If n is a positive integer, greater than 1, then 21/n is irrational.
 

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