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Is it possible to create a higher energy photon from two lower ones?

  1. May 29, 2013 #1
    Is it possible for two photons to join their energy to structure a one photon of higher frequency?
    join.png
    Let's assume that the two incoming (IR) photons are prepared specially: coming in the same time, same wavelength, phase, appropriate (complementer) spins and angle, etc. They arrive the appropriate atom and giving the energy at the same time. The atom gets energized and releases one single photon (UV) with the double energy.

    1. This is possible... OK, but why this is not happening in case of the photoelectric effect?
    2. This is not possible, because of ... (the energy-time uncertainty?).

    What do you think?
    Thanks for the anwsers in advance.
     
  2. jcsd
  3. May 29, 2013 #2
    No, it's not possible by conservation of angular momentum. The photon is spin-1, which ordinarily means that possible values for the spin along some axis (say, the z-axis) are +1, 0, and -1. Because it's massless, the longitudinal polarization state is forbidden and the z-component can only be +1 or -1. Hence, for two photons, the total z-component of angular momentum will be +2, 0, or -2. However, the outgoing photon will be +1 or -1. Hence, conservation of angular momentum would be violated by this process.
     
  4. May 29, 2013 #3
    OK, and what is the difference if we are using a twophoton?

    splitandjoin.png

    I mean let's imagine an experiment when we split an IR photon to a twophoton and then we try to join them? Or it is also not possible? Is the photon splitting an irreversible process?
     
  5. May 29, 2013 #4

    fluidistic

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  6. May 29, 2013 #5
    Thank you, I have found this in the thread:
    Am I understand well that if a special matter contributed, LastOneStanding's explanation about the spins is not always prevents the join?
     
  7. May 30, 2013 #6

    Demystifier

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    Due to angular momentum conservation the mentioned process is not possible in vacuum, but is probably possible in a medium.
     
  8. May 30, 2013 #7
    Great, thank you. Please make it clear for me: if there is a lonely atom involved in the effect (like the case on the figure) is it count as a medium?
    Would you be so kind and explain a little more how the spin problem is solved by a medium?
    Thank you in advance.
     
  9. May 31, 2013 #8

    Demystifier

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    In principle, yes.

    The medium can take the missing angular momentum, so that the total angular momentum is conserved.

    The process has still a very low probability (essentially because it typically requires a decrease of total entropy), but the time-inverted process - parametric down-conversion - is often produced in laboratories.
    http://en.wikipedia.org/wiki/Parametric_down-conversion
    In this case the medium is a nonlinear crystal.
     
  10. May 31, 2013 #9
    Very good, this is exactly what I was thinking about the problem, but I was uncertain.

    Thank you very much!
     
  11. May 31, 2013 #10
    From the Wiki article: "A nonlinear crystal is used to split photons into pairs of photons that, in accordance with the law of conservation of energy, have combined energies and momenta equal to the energy and momentum of the original photon, are phase-matched in the frequency domain, and have correlated polarizations. (The state of the crystal is unchanged by the process.)"

    Is this a mistake? How can the state of the crystal be unchanged when it needs to pick up the difference in angular momenta from the incoming and outgoing photons? I agree it must do—and obviously such processes due occur since down conversion with non-linear media is done regularly—but this seems at odds with the article. The citation for that paragraph is a book I don't have access to.
     
  12. May 31, 2013 #11
    I have an idea about it. Maybe one of the electrons in the shell of the medium atom changes its spin. The crystal (structure) itself remains unchanged (in avarage at least). Please correct me if I'm wrong.
     
  13. May 31, 2013 #12
    Well, that's what I assumed happens but then I would strongly dispute the wording that "The state of the crystal is unchanged by the process." The overall state of the crystal includes the spin states of its electrons.
     
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