Is it possible to find orbital velocity depending on time?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
hmvince
Messages
44
Reaction score
0
A satellite is in orbit around earth,
(you know G, mass of earth, etc. but NOT the radius)
is it possible to find orbital period?
 
Physics news on Phys.org
hmvince said:
A satellite is in orbit around earth,
(you know G, mass of earth, etc. but NOT the radius)
is it possible to find orbital period?

If only G and mass are all that is known, then No. According to Kepler's Law you must know the radius to get the orbital period, (or vice versa). All you can determine with only G and M is the ratio of the orbital period squared to the radius cubed...which is equal to 4(pi)^2 / GM.

Creator
 
Sorry about the late reply, but thankyou very much.
If it's not too much trouble, when calculating the mass of the Earth using the moon as a reference and Kepler's 3rd Law, is it correct to subtract the moon's mass after completing the sum:

Code:
m[SUB]e[/SUB] = (4*(pi)[SUP]2[/SUP]*r[SUP]3[/SUP]) / (G*t[SUP]2[/SUP])

m[SUB]e[/SUB] = (4*(pi)[SUP]2[/SUP]*385000000[SUP]3[/SUP]) / (G*2358720[SUP]2[/SUP])

m[SUB]e[/SUB] = 6.07[SUB]E[/SUB]+24

Should I be subtracting the moons mass to get:

Code:
m[SUB]e[/SUB] = 6.07[SUB]E[/SUB]+24 - 7.36[SUB]e[/SUB]+22  =   5.99[SUB]E[/SUB]+24

I know its not a big difference but I would like to be doing this correctly.
Thanks very much