Is it possible to find uncertainty for water hardness?

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SUMMARY

The discussion focuses on calculating the uncertainty in water hardness measurement through titration, specifically using 281.75 mL of titrant to determine a hardness of 532.08 ppm. The remediation process involves the use of a 0.005 M Ca(NO3)2 aqueous solution to address fluoride contamination. The relevant chemical equations include the dissociation of Ca(NO3)2 and the precipitation reaction forming CaF2, with the solubility product constant (Ksp) of CaF2 being 3.45 x 10^-11. The remediation variable identified for further study is the fluoride ion concentration ([F-]).

PREREQUISITES
  • Understanding of titration techniques and calculations
  • Knowledge of chemical equilibrium and Ksp calculations
  • Familiarity with aqueous solution chemistry, particularly calcium and fluoride interactions
  • Basic skills in uncertainty analysis in experimental data
NEXT STEPS
  • Research how to calculate uncertainty in titration results
  • Study the principles of chemical equilibrium and Ksp in detail
  • Learn about the remediation of fluoride using calcium compounds
  • Explore advanced titration techniques and their applications in water quality analysis
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Chemistry students, environmental scientists, and laboratory technicians involved in water quality testing and remediation processes.

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Homework Statement


I am told to find the uncertainty for the titration part of determining the water hardness in my chemistry lab. I only have the following data:

By titrating 281.75 mL of titrant, it was determined that 532.08 ppm is the hardness of the water.Also, for water remediation, my contaminant was fluoride, and my remediation agent was 0.005 M Ca(NO3)2 aqueous solution. What is the cheimcal equation describing remediation chemistry, and what is the remediation variable to be studied?

Homework Equations


No clue

The Attempt at a Solution


I cannot find any equations that will help me, since I do not have the "actual" value that I can use to determine uncertainty. If anyone is able to help me, it'd be great. Thanks!
 
Last edited:
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Ca(NO3)2 <-------> Ca+2 + 2NO3-

Ca+2 + 2F- <---------> CaF2(s)

Ksp of CaF2 = [Ca+2][F-]^2 = 3.45 X 10^-11

Remediation variable = [F-]
 

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