Is it Possible to Turn a Car Without Skidding?

  • Thread starter Thread starter PhizKid
  • Start date Start date
  • Tags Tags
    Car Turning
Click For Summary
SUMMARY

The discussion centers on the physics of turning a car without skidding, utilizing the equations of motion and frictional forces. The key equations derived are for minimum and maximum velocities, specifically vmin = 0 and vmax = ∞, indicating that any speed within the range of 0 to infinity will prevent skidding. The analysis emphasizes the role of centripetal force and friction in maintaining a circular path during a turn. The conclusion confirms that the text implies "all speeds are possible" for maintaining control without skidding.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of centripetal force and its role in circular motion
  • Familiarity with friction coefficients and their impact on motion
  • Basic algebra for manipulating equations of motion
NEXT STEPS
  • Study the effects of different friction coefficients on vehicle dynamics
  • Explore advanced topics in circular motion, including angular momentum
  • Learn about vehicle stability control systems and their role in preventing skidding
  • Investigate real-world applications of these principles in automotive engineering
USEFUL FOR

Physics students, automotive engineers, and anyone interested in vehicle dynamics and safety during turns.

PhizKid
Messages
477
Reaction score
2

Homework Statement


sNxzE.png



Homework Equations


F = ma

The Attempt at a Solution


First off, to keep the car from skidding to the side we want it to be constrained to move in a circle about the center of the turn because if it skids then it has deviated / veered off tangentially at some point along a circular path. For the minimum velocity, we want friction to point in the direction away from the center so that the net centripetal force is less thus requiring a minimal velocity. The equations of motion for the car are Nsin\theta - fcos\theta = M\frac{v_{min}^{2}}{R}, Ncos\theta + fsin\theta - Mg = 0 which tells us that v_{min}^{2} = gR\frac{tan\theta - \mu }{1 + \mu tan\theta }. For the maximum case we just negate the direction of friction and this gives us, in a very similar way, v_{max}^{2} = gR\frac{tan\theta + \mu }{1 - \mu tan\theta }. Plugging in the parameters give in the ans. clue we see that v_{min} = 0, v_{max} = \infty so any speed in the range 0 \leq v< \infty will keep it from skidding which is all possible speeds. Is that what the text means by "all speeds are possible"? Thanks!
 
Physics news on Phys.org
Yes.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
4K
Replies
4
Views
3K
Replies
16
Views
3K
  • · Replies 27 ·
Replies
27
Views
5K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
7
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
5
Views
5K