Is k an Eigenvalue of A with Sum of Row Entries as k?

Click For Summary
SUMMARY

The discussion centers on the question of whether a square matrix A, where the sum of the entries of each row equals a constant k, has k as an eigenvalue. The relevant equation is Ax - λx = 0, leading to the characteristic polynomial (1-k)(k-λ) - k = 0. The inquiry also seeks to identify a corresponding eigenvector that results in the vector (k, k, k, ..., k)T when multiplied by A. The conclusion is that k is indeed an eigenvalue of A, with the corresponding eigenvector being a vector of ones.

PREREQUISITES
  • Understanding of eigenvalues and eigenvectors
  • Familiarity with matrix algebra
  • Knowledge of characteristic polynomials
  • Proficiency in solving linear equations
NEXT STEPS
  • Study the properties of eigenvalues in square matrices
  • Learn about the implications of row sums on eigenvalues
  • Explore the derivation of characteristic polynomials
  • Investigate the relationship between eigenvectors and matrix transformations
USEFUL FOR

Students studying linear algebra, mathematicians interested in matrix theory, and educators teaching eigenvalue concepts.

mjthiry
Messages
1
Reaction score
0
1. Homework Statement

Suppose that A is a square matrix and the sum of the entries of each row is some number k. Is k an eigenvalue of A? if so, what is the corresponding Eigenvector?2. Homework Equations

Ax-λx=0
3. The Attempt at a Solution

(1-k)(K-λ)-k=0I am not sure how to solve this in a proof sense ( since we are not using specific numbers)
 
Last edited:
Physics news on Phys.org
Is there a vector can you multiply into A where the product will be (k, k, k, ..., k)T?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 5 ·
Replies
5
Views
14K
  • · Replies 2 ·
Replies
2
Views
2K