Is Ligand Binding Cooperative and How Many Binding Sites Does the Protein Have?

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SUMMARY

The discussion focuses on determining the cooperativity of ligand binding and the number of binding sites for a protein with a concentration of 10^-3 M. The Hill equation is utilized, expressed as log Y/(1-Y) = n log [A] - log K_d, where Y represents the fraction of binding sites occupied. Participants noted inconsistencies in the plotted data, with slopes varying significantly, indicating potential issues in calculating the concentration of free ligand A. The need for clarity in the data presentation was emphasized to facilitate accurate analysis.

PREREQUISITES
  • Understanding of the Hill equation in biochemistry
  • Knowledge of ligand binding dynamics
  • Familiarity with graphing techniques for data analysis
  • Ability to calculate dissociation constants (K_d)
NEXT STEPS
  • Learn how to accurately plot data using the Hill equation
  • Research methods for calculating free ligand concentrations in solution
  • Explore techniques for determining binding site numbers in proteins
  • Study the implications of cooperativity in ligand binding
USEFUL FOR

This discussion is beneficial for biochemists, molecular biologists, and researchers studying protein-ligand interactions, particularly those analyzing binding cooperativity and site occupancy in proteins.

kittybobo1
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Homework Statement



The binding of a ligand B to a protein is studied. The protein concentration it 10^-3 M. The amounts bound,b, for each added is given as the following:

(M) (b)(M)
.001 5*10^-6
.002 3.3*10^-3
.005 3.78*10^-3
.007 4.72*10^-3
.01 4.95*10^-3
.02 5*10^-3
.05 5*10^-3

Find if it is cooperative, the number of binding sites, and K_d

Homework Equations



The hills equation can be expressed as log Y/(1-Y) =n log [A] - log K_d


The Attempt at a Solution



So the y intercept is - log K_d and the slope is n when you plot the left side in respect to log [A]. Y is the fractions filled, so I think it would be (b)/(5*10^-3). But, plotting the graph.. it seems a little screwy.. the plot goes from slope of 10.9 to .5 then to ~5.. The graph is shown here.
 
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kittybobo1 said:
So the y intercept is - log K_d and the slope is n when you plot the left side in respect to log [A]. Y is the fractions filled, so I think it would be (b)/(5*10^-3). But, plotting the graph.. it seems a little screwy.. the plot goes from slope of 10.9 to .5 then to ~5.. The graph is shown here.

If it were I could probably help, but I can't see it.:confused:

Possible sources of confusion:
1) [A] in your equation is concentration of free A in solution, did you calculate that?;
2) That's enough possible sources of confusion till I see your graph. :-p

And to make it easier for us and yourself put also the free A in a table with the other parameters.
 
Last edited:

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